A repair bill on a sailboat came to \$2356, including \$826 for parts and the remainder for labor. If the cost of labor is \$90 per hour, how many hours of labor did it take to repair the sailboat?
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
Problem 25
Textbook Question
A rectangular soccer field is twice as long as it is wide. If the perimeter of the soccer field is 300 yards, what are its dimensions?
Verified step by step guidance1
Let the width of the soccer field be represented by \(w\) yards.
Since the length is twice the width, express the length as \$2w$ yards.
Recall the formula for the perimeter of a rectangle: \(P = 2 \times (\text{length} + \text{width})\).
Substitute the given perimeter and expressions for length and width into the formula: \$300 = 2 \times (2w + w)$.
Simplify the equation and solve for \(w\), then use the value of \(w\) to find the length \$2w$.
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
2mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Perimeter of a Rectangle
The perimeter of a rectangle is the total distance around it, calculated by adding twice the length and twice the width (P = 2L + 2W). Understanding this formula is essential to relate the given perimeter to the dimensions of the soccer field.
Algebraic Representation of Relationships
Translating the problem's conditions into algebraic expressions is crucial. Here, the length is twice the width, so L = 2W. This relationship allows substitution into the perimeter formula to form an equation with one variable.
Recommended video:
Guided course
Introduction to Algebraic Expressions
Solving Linear Equations
Once the equation is set up, solving for the unknown variable involves combining like terms and isolating the variable. This step yields the width, which can then be used to find the length, providing the field's dimensions.
Recommended video:
Solving Linear Equations with Fractions
Watch next
Master Introduction to Solving Linear Equtions with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Textbook Question
476
views
