For an international telephone call, a telephone company charges \$0.43 for the first minute, \$0.32 for each additional minute, and a \$2.10 service charge. If the cost of a call is \$5.73, how long did the person talk?
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
Problem 27
Textbook Question
The length of the rectangular tennis court at Wimbledon is 6 feet longer than twice the width. If the court's perimeter is 228 feet, what are the court's dimensions?
Verified step by step guidance1
Define variables for the dimensions of the tennis court: let the width be \(w\) feet, and the length be \(l\) feet.
Express the length in terms of the width using the given relationship: \(l = 2w + 6\).
Recall the formula for the perimeter of a rectangle: \(P = 2l + 2w\). Substitute the given perimeter value: \$228 = 2l + 2w$.
Substitute the expression for \(l\) from step 2 into the perimeter equation: \$228 = 2(2w + 6) + 2w$.
Simplify and solve the resulting equation for \(w\), then use the value of \(w\) to find \(l\) using \(l = 2w + 6\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Formulating Algebraic Expressions from Word Problems
This involves translating verbal descriptions into mathematical expressions or equations. For example, 'the length is 6 feet longer than twice the width' can be written as L = 2W + 6, where L is length and W is width.
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Introduction to Algebraic Expressions
Perimeter of a Rectangle
The perimeter of a rectangle is the total distance around it, calculated as P = 2(L + W), where L is length and W is width. This formula helps relate the dimensions to the given perimeter value.
Solving Linear Equations
Once the problem is expressed as an equation, solving linear equations involves isolating variables to find their values. This includes combining like terms and using inverse operations to solve for unknowns.
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Solving Linear Equations with Fractions
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