What is the probability that a card player draws two aces from a standard deck of 52 cards if they keep the first card after drawing it?
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'And' Probabilities (Multiplication Rule)
Multiple Choice
About 15% of people in a town have both a cat and a dog. As 64% of residents have a dog, what is the probability that someone in the town owns a cat, given they have a dog?
A
0.23
B
0.15
C
0.64
D
0.096
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Verified step by step guidance1
Step 1: Recognize that this is a conditional probability problem. The formula for conditional probability is P(A|B) = P(A ∩ B) / P(B), where P(A|B) is the probability of event A given event B, P(A ∩ B) is the probability of both events A and B occurring, and P(B) is the probability of event B.
Step 2: Define the events in the problem. Let A represent the event 'a person owns a cat' and B represent the event 'a person owns a dog.' The problem provides P(A ∩ B) = 0.15 (probability of owning both a cat and a dog) and P(B) = 0.64 (probability of owning a dog).
Step 3: Substitute the given values into the conditional probability formula. Using P(A|B) = P(A ∩ B) / P(B), substitute P(A ∩ B) = 0.15 and P(B) = 0.64.
Step 4: Simplify the fraction to calculate P(A|B). This will give the probability that someone owns a cat, given that they own a dog.
Step 5: Interpret the result. The final value represents the likelihood of a person owning a cat if it is already known that they own a dog.
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