A library has chosen to select the two monthly book club reads by randomly choosing two books from a list of top 100 adult reads posted in the local newspaper. On the list, 62 books are fiction and 38 books are nonfiction. What is the probability of choosing two nonfiction books for this month's book club meeting?
Table of contents
- 1. Critical Thinking & Problem Solving1h 59m
- 2. Sets4h 25m
- 3. Logic4h 33m
- 4. Numeration Systems3h 14m
- 5. The Real Number System3h 5m
- 6. Algebra Review8h 46m
- Evaluating Algebraic Expressions15m
- Simplifying Algebraic Expressions1h 2m
- Linear Equations41m
- Direct & Inverse Variation27m
- Linear Inequalities in One Variable41m
- Quadratic Equations1h 24m
- Rectangular Coordinate System28m
- Intro to Functions and Notation29m
- Domain and Range10m
- Using Intercepts to Graph Lines4m
- Slope and Slope-Intercept Form58m
- Systems of Linear Equations1h 25m
- Systems of Linear Inequalities37m
- 7. Exponential Growth54m
- 10. Geometry3h 37m
- 11. Voting and Apportionment3h 3m
- 12. Graph Theory3h 1m
- 13. Counting & Probability1h 55m
13. Counting & Probability
'And' Probabilities (Multiplication Rule)
Multiple Choice
What is the probability that a card player draws two aces from a standard deck of 52 cards if they keep the first card after drawing it?
A
0.0035
B
0.0059
C
0.0045
D
0.0044
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Verified step by step guidance1
Step 1: Understand the problem. A standard deck of cards has 52 cards, and there are 4 aces in the deck. The player draws two cards sequentially, keeping the first card after drawing it. This means the total number of cards remains 52 for both draws.
Step 2: Calculate the probability of drawing an ace on the first draw. Since there are 4 aces in the deck, the probability is given by \( P(\text{First Ace}) = \frac{4}{52} \).
Step 3: Calculate the probability of drawing an ace on the second draw. Since the first card is kept, the total number of cards remains 52, and there are still 4 aces in the deck. Thus, the probability is \( P(\text{Second Ace}) = \frac{4}{52} \).
Step 4: Multiply the probabilities of the two independent events (drawing an ace on the first draw and drawing an ace on the second draw). The combined probability is \( P(\text{Two Aces}) = P(\text{First Ace}) \times P(\text{Second Ace}) = \frac{4}{52} \times \frac{4}{52} \).
Step 5: Simplify the expression \( \frac{4}{52} \times \frac{4}{52} \) to find the final probability. This will give you the probability of drawing two aces under the given conditions.
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