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Enter known values

If you enter grams, provide molar mass to convert when needed. If both values are in moles, no molar mass is needed.

Use the same basis for comparison (both grams or both moles). The calculator converts consistently when molar mass is provided.

Leave one field blank (actual, theoretical, or percent) and we’ll solve it from the other two.

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Chips prefill typical cases. We’ll convert grams↔moles consistently when molar mass is given.

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No results yet. Enter two values and click Calculate.

How this calculator works

  • Definition: % yield = (actual / theoretical) × 100.
  • Input rules: Provide any two of {actual, theoretical, percent}; we solve the third.
  • Units: Compare on the same basis — both grams or both moles. If you enter grams, use molar mass to convert.
  • Tip: Theoretical yield is set by stoichiometry and the limiting reagent.

Formula & Equation Used

Percent yield: % = (actual / theoretical) × 100

Rearrangements: actual = (%/100)·theoretical;   theoretical = actual / (%/100)

Example Problems & Step-by-Step Solutions

Example 1 — Compute percent yield

Actual = 7.20 g, Theoretical = 9.00 g → % = (7.20/9.00)×100 = 80.0%.

Example 2 — Compute actual yield

% = 92.0%, Theoretical = 25.0 g → Actual = 0.92×25.0 = 23.0 g.

Example 3 — Mixed units (grams ↔ moles)

Actual = 3.50 g of glucose (M=180.16 g·mol⁻¹) → 0.0194 mol.
Theoretical = 0.0250 mol → % = (0.0194/0.0250)×100 ≈ 77.6%.

Frequently Asked Questions

Q: Why can percent yield exceed 100%?

Usually due to impurities or solvent; the measured mass is artificially high.

Q: Do I always need molar mass?

Only if you compare grams to moles. If both amounts are in moles (or both in grams), you can compute directly.

Q: Is theoretical yield the same as limiting reagent?

The limiting reagent determines the theoretical yield via stoichiometry; the values aren’t the same, but they’re linked.

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