Solve each equation. Give solutions in exact form. See Examples 5–9. log5 [(3x + 5)(x + 1)] = 1
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
6. Exponential & Logarithmic Functions
Solving Exponential and Logarithmic Equations
Problem 60
Textbook Question
Solve each equation. Give solutions in exact form. See Examples 5–9. log(3x + 5) - log(2x + 4) = 0
Verified step by step guidance1
Recall the logarithmic property that states \( \log_a M - \log_a N = \log_a \left( \frac{M}{N} \right) \). Apply this to the equation \( \log(3x + 5) - \log(2x + 4) = 0 \) to combine the logs into a single logarithm: \( \log \left( \frac{3x + 5}{2x + 4} \right) = 0 \).
Use the definition of logarithm: if \( \log_b A = C \), then \( A = b^C \). Since the base is 10 (common logarithm), rewrite the equation as \( \frac{3x + 5}{2x + 4} = 10^0 \).
Simplify the right side since \( 10^0 = 1 \), so the equation becomes \( \frac{3x + 5}{2x + 4} = 1 \).
Solve the resulting equation by cross-multiplying: \( 3x + 5 = 2x + 4 \). Then isolate \( x \) by subtracting \( 2x \) and 4 from both sides.
Check the solution(s) by substituting back into the original logarithmic expressions to ensure the arguments \( 3x + 5 \) and \( 2x + 4 \) are positive, since the logarithm is only defined for positive arguments.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Properties of Logarithms
Understanding the properties of logarithms, especially the subtraction rule log(a) - log(b) = log(a/b), is essential. This allows combining or simplifying logarithmic expressions to solve equations more easily.
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Change of Base Property
Solving Logarithmic Equations
Solving logarithmic equations involves rewriting the equation using log properties, then converting the logarithmic form to an exponential form to isolate the variable. This step is crucial to find exact solutions.
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Solving Logarithmic Equations
Domain Restrictions in Logarithms
Since logarithms are only defined for positive arguments, it is important to determine the domain restrictions by setting the inside of each log greater than zero. This ensures that solutions are valid and do not produce undefined expressions.
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Domain Restrictions of Composed Functions
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