Work each of the following. Find the equation of a circle with center at (-4, 3), passing through the point (5, 8).Write it in center-radius form.
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- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
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Intro to Functions & Their Graphs
Problem 67
Textbook Question
Graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. x² + y² = 16, x-y = 4
Verified step by step guidance1
Identify the two given equations: the first is a circle equation \(x^{2} + y^{2} = 16\), and the second is a linear equation \(x - y = 4\).
From the linear equation \(x - y = 4\), solve for one variable in terms of the other. For example, express \(x\) as \(x = y + 4\).
Substitute the expression for \(x\) from the linear equation into the circle equation. This gives \( (y + 4)^{2} + y^{2} = 16 \).
Expand and simplify the resulting equation to form a quadratic equation in terms of \(y\). Then solve this quadratic equation to find the possible \(y\)-values.
Use the \(y\)-values found to calculate the corresponding \(x\)-values using \(x = y + 4\). These \((x, y)\) pairs are the points of intersection. Finally, verify each point by substituting back into both original equations.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Graphing Circles
The equation x² + y² = 16 represents a circle centered at the origin with radius 4. Understanding how to graph this circle involves plotting all points (x, y) that satisfy the equation, which lie exactly 4 units from the origin in all directions.
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Graphing Linear Equations
The equation x - y = 4 is a linear equation representing a straight line. To graph it, rewrite it in slope-intercept form (y = x - 4) and plot points accordingly. This line will intersect the circle at points where both equations hold true.
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Finding Points of Intersection
Points of intersection satisfy both equations simultaneously. To find them, substitute the linear equation into the circle's equation and solve for x and y. These solutions correspond to the coordinates where the circle and line cross on the graph.
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