Textbook QuestionThe rule for rewriting an absolute value equation without absolute value bars can be extended to equations with two sets of absolute value bars: If u and v represent algebraic expressions, then |u| = |v| is equivalent to u = v or u = - v. Use this to solve the equations in Exercises 77–84. ∣2x2−4∣=∣2x2∣|2x^2 - 4| = |2x^2| 605views
Textbook QuestionUse the method described in Exercises 83–86, if applicable, and properties of absolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 can be solved by inspection.) | x2 + 1 | - | 2x | = 0494views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = x2 - 2x + 292views
Textbook QuestionAnswer each question. Find the values of a, b, and c for which the quadratic equation. ax2+bx+c=0ax^2 + bx + c = 0 has the given numbers as solutions. (Hint: Use the zero-factor property in reverse.)−3,2-3, 2 1082views1rank
Textbook QuestionAnswer each question. Find the values of a, b, and c for which the quadratic equation. ax2+bx+c=0ax^2 + bx + c = 0 has the given numbers as solutions. (Hint: Use the zero-factor property in reverse.)4,54, 5 1444views