Write each formula as an English phrase using the word varies or proportional. C=2πr, where C is the circumference of a circle of radius r.
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- 5. Rational Functions1h 23m
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1. Equations & Inequalities
Rational Equations
Problem 29
Textbook Question
Resistance of a Wire The resistance in ohms of a platinum wire temperature sensor varies directly as the temperature in kelvins (K). If the resistance is 646 ohms at a temperature of 190 K, find the resistance at a temperature of 250 K.
Verified step by step guidance1
Identify the direct variation relationship: resistance \(R\) varies directly as temperature \(T\), which can be written as \(R = k \times T\), where \(k\) is the constant of proportionality.
Use the given values to find \(k\): substitute \(R = 646\) ohms and \(T = 190\) K into the equation \$646 = k \times 190$.
Solve for \(k\) by dividing both sides of the equation by 190: \(k = \frac{646}{190}\).
Write the general formula for resistance using the found \(k\): \(R = \left( \frac{646}{190} \right) \times T\).
Find the resistance at \(T = 250\) K by substituting into the formula: \(R = \left( \frac{646}{190} \right) \times 250\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Direct Variation
Direct variation describes a relationship where one quantity changes proportionally with another. If resistance varies directly with temperature, then resistance = k × temperature, where k is a constant. Understanding this helps set up the equation to find unknown values.
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Finding the Constant of Variation
To solve direct variation problems, first find the constant k by using given values. Substitute the known resistance and temperature into the formula resistance = k × temperature, then solve for k. This constant allows calculation of resistance at any temperature.
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Solving Linear Equations
Once the constant k is found, substitute the new temperature into the equation and solve for resistance. This involves basic algebraic manipulation to isolate the variable and compute the desired value, reinforcing skills in solving linear equations.
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