In Exercises 25–34, use mathematical induction to prove that each statement is true for every positive integer n. n Σ (i = 1) 5 · 6i = 6(6n - 1)
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
9. Sequences, Series, & Induction
Sequences
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The first 4 terms of a sequence are {3,23,33,43,…}. Continuing this pattern, find the 7th term.
A
83
B
63
C
73
D
93
Verified step by step guidance1
Identify the pattern in the sequence. The given sequence is {3\sqrt{3}, 2\cdot3\sqrt{3}, 3\cdot3\sqrt{3}, 4\cdot3\sqrt{3}, \ldots}. Notice that each term can be expressed as n\cdot3\sqrt{3}, where n is the term number.
To find the 7th term, substitute n = 7 into the expression for the nth term. This gives us 7\cdot3\sqrt{3}.
Simplify the expression 7\cdot3\sqrt{3} to get 21\sqrt{3}.
Verify the pattern by checking the first few terms: for n = 1, 2, 3, 4, the terms are 3\sqrt{3}, 6\sqrt{3}, 9\sqrt{3}, 12\sqrt{3}, respectively, which matches the given sequence.
Conclude that the 7th term in the sequence is 21\sqrt{3}.
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