Solve each problem using a system of equations in two variables. See Example 6. Find two numbers whose squares have a sum of 100 and a difference of 28.
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
7. Systems of Equations & Matrices
Two Variable Systems of Linear Equations
Problem 17
Textbook Question
Solve each nonlinear system of equations. Give all solutions, including those with nonreal complex components.
y = x2 - 2x + 1
x - 3y = -1
Verified step by step guidance1
Start with the given system of equations:
\(y = x^{2} - 2x + 1\)
and
\(x - 3y = -1\).
Substitute the expression for \(y\) from the first equation into the second equation to eliminate \(y\). This gives:
\(x - 3(x^{2} - 2x + 1) = -1\).
Expand and simplify the equation:
\(x - 3x^{2} + 6x - 3 = -1\)
which simplifies to
\(-3x^{2} + 7x - 3 = -1\).
Bring all terms to one side to form a quadratic equation:
\(-3x^{2} + 7x - 3 + 1 = 0\)
which simplifies to
\(-3x^{2} + 7x - 2 = 0\).
Solve the quadratic equation for \(x\) using the quadratic formula:
\(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)
where \(a = -3\), \(b = 7\), and \(c = -2\). After finding the values of \(x\), substitute each back into the original equation for \(y\) to find the corresponding \(y\) values.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nonlinear Systems of Equations
A nonlinear system involves at least one equation that is not linear, such as quadratic or higher-degree polynomials. Solving these systems requires methods that handle curves and more complex relationships, unlike linear systems which involve straight lines.
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Substitution Method
The substitution method involves solving one equation for one variable and substituting that expression into the other equation. This reduces the system to a single equation with one variable, making it easier to solve, especially when one equation is already solved for a variable.
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Complex Solutions
When solving polynomial equations, solutions may include nonreal complex numbers involving the imaginary unit i. Recognizing and including complex solutions ensures all possible roots are found, which is essential for a complete solution to nonlinear systems.
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