The functions in Exercises 11-28 are all one-to-one. For each function, a. Find an equation for f-1(x), the inverse function. b. Verify that your equation is correct by showing that f(ƒ-1 (x)) = = x and ƒ-1 (f(x)) = x. f(x) = 2x
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
3. Functions
Function Composition
Problem 7
Textbook Question
Find f(g(x)) and g (f(x)) and determine whether each pair of functions ƒ and g are inverses of each other. f(x) = 3/(x-4) and g(x) = (3/x) + 4
Verified step by step guidance1
First, recall that the composition of functions f(g(x)) means substituting g(x) into every x in f(x). So, write down f(g(x)) as f\left(g(x)\right) = f\left(\frac{3}{x} + 4\right).
Next, substitute g(x) = \frac{3}{x} + 4 into f(x) = \frac{3}{x - 4}. This gives f(g(x)) = \frac{3}{\left(\frac{3}{x} + 4\right) - 4}.
Simplify the denominator of f(g(x)) by combining like terms inside the parentheses: \left(\frac{3}{x} + 4\right) - 4 = \frac{3}{x}. So, f(g(x)) = \frac{3}{\frac{3}{x}}.
Now, simplify the complex fraction \frac{3}{\frac{3}{x}} by multiplying numerator and denominator appropriately, which will simplify to x.
Repeat the process for g(f(x)): substitute f(x) into g(x), so g(f(x)) = g\left(\frac{3}{x - 4}\right) = \frac{3}{\frac{3}{x - 4}} + 4, then simplify this expression step-by-step. Finally, check if both compositions simplify to x, which would indicate that f and g are inverses.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Function Composition
Function composition involves applying one function to the result of another, denoted as f(g(x)) or g(f(x)). It requires substituting the entire expression of one function into the variable of the other, allowing us to analyze combined transformations or operations.
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Inverse Functions
Two functions f and g are inverses if composing them in either order returns the input, meaning f(g(x)) = x and g(f(x)) = x. This relationship shows that each function reverses the effect of the other, effectively undoing the transformation.
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Graphing Logarithmic Functions
Rational Functions and Domain Restrictions
Rational functions are ratios of polynomials and may have restrictions where the denominator is zero. Understanding these domain restrictions is crucial when composing functions or checking inverses to avoid undefined expressions and ensure valid operations.
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Domain Restrictions of Composed Functions
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