Identify the inequality given: \(x + 2y \leq 6\). This represents a linear inequality in two variables.
Rewrite the inequality in slope-intercept form by isolating \(y\): subtract \(x\) from both sides to get \$2y \leq 6 - x\(, then divide both sides by 2 to obtain \)y \leq \frac{6 - x}{2}$.
Graph the boundary line \(y = \frac{6 - x}{2}\). Since the inequality is \(\leq\), the boundary line should be solid, indicating points on the line satisfy the inequality.
Determine which side of the boundary line to shade by testing a point not on the line, such as the origin \((0,0)\). Substitute into the inequality: \$0 + 2(0) \leq 6\( which simplifies to \)0 \leq 6\(, a true statement, so shade the region containing \)(0,0)$.
Shade the region below or on the line \(y = \frac{6 - x}{2}\) to represent all solutions to the inequality \(x + 2y \leq 6\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Graphing Linear Inequalities
Graphing linear inequalities involves first graphing the related linear equation as a boundary line. The inequality symbol determines whether the boundary is solid (≤ or ≥) or dashed (< or >). The solution region is the set of points that satisfy the inequality, typically shaded on one side of the boundary line.
Rearranging the inequality into slope-intercept form (y = mx + b) helps in graphing. For x + 2y ≤ 6, solving for y gives y ≤ (-1/2)x + 3. This form clearly shows the slope and y-intercept, making it easier to plot the boundary line accurately.
After graphing the boundary line, select a test point not on the line (often the origin) to check if it satisfies the inequality. If the test point satisfies the inequality, shade the region containing that point; otherwise, shade the opposite side. This confirms the correct solution area.