Work each problem. Elmer borrowed \$3150 from his brother Julio to pay for books and tuition. He agreed to repay Julio in 6 months with simple annual interest at 4%. How much will the interest amount to?
Ch. 1 - Equations and Inequalities

Chapter 2, Problem 59
Solve each equation. √3x=√(5x+1)-1
Verified step by step guidance1
Start with the given equation: \(\sqrt{3x} = \sqrt{5x + 1} - 1\).
Isolate one of the square root terms by adding 1 to both sides: \(\sqrt{3x} + 1 = \sqrt{5x + 1}\).
Square both sides of the equation to eliminate the square roots: \(\left(\sqrt{3x} + 1\right)^2 = \left(\sqrt{5x + 1}\right)^2\).
Expand the left side using the formula \((a + b)^2 = a^2 + 2ab + b^2\): \(3x + 2\sqrt{3x} + 1 = 5x + 1\).
Simplify the equation and isolate the remaining square root term, then square both sides again to solve for \(x\).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Square Root Equations
Square root equations involve variables under a radical sign. To solve them, isolate the square root expression and then square both sides to eliminate the radical. This process may introduce extraneous solutions, so checking all solutions in the original equation is essential.
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Isolating Variables
Isolating the variable means manipulating the equation to get the variable alone on one side. This step is crucial before squaring both sides to avoid complicating the equation further. Proper isolation helps simplify the solving process and reduces errors.
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Equations with Two Variables
Checking for Extraneous Solutions
Squaring both sides of an equation can introduce solutions that do not satisfy the original equation. These are called extraneous solutions. Always substitute the found solutions back into the original equation to verify which ones are valid.
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Restrictions on Rational Equations
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