Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Rational Equations
Problem 78
Textbook Question
Solve the variation problems in Exercises 77–82. The distance that a body falls from rest is directly proportional to the square of the time of the fall. If skydivers fall 144 feet in 3 seconds, how far will they fall in 10 seconds?
Verified step by step guidance1
Identify the type of variation: The problem states that the distance (d) is directly proportional to the square of the time (t). This can be expressed as d = k * t^2, where k is the constant of proportionality.
Use the given information to find the constant of proportionality (k): Substitute d = 144 and t = 3 into the equation d = k * t^2. Solve for k by isolating it on one side of the equation.
Write the general equation with the calculated value of k: Once k is determined, substitute it back into the equation d = k * t^2 to get the specific equation for this situation.
Substitute t = 10 into the specific equation: Use the equation from the previous step and replace t with 10 to find the distance (d) the skydivers fall in 10 seconds.
Simplify the expression to find the distance: Perform the necessary calculations to simplify the expression and determine the distance the skydivers fall in 10 seconds.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Direct Proportionality
Direct proportionality means that two quantities increase or decrease in tandem at a constant ratio. In this context, the distance fallen by a body is directly proportional to the square of the time, which can be expressed mathematically as d = k * t^2, where d is distance, t is time, and k is a constant of proportionality.
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Quadratic Relationships
Quadratic relationships involve equations where the variable is raised to the second power, resulting in a parabolic graph. In this problem, since distance is proportional to the square of time, the relationship can be modeled as a quadratic function, which helps in predicting distances for different time intervals.
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Unit Conversion and Scaling
Unit conversion and scaling are essential for solving problems involving different measurements. In this case, understanding how to scale the distance fallen based on the time squared allows us to calculate the distance for 10 seconds by using the known distance for 3 seconds and applying the proportionality constant derived from that relationship.
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Related Practice
Textbook Question
Use the four-step procedure for solving variation problems given on page 447 to solve Exercises 1–10.y varies jointly as x and z. y = 25 when x = 2 and z = 5. Find y when x = 8 and z = 12.
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