Use mathematical induction to prove that each statement is true for every positive integer n. 6 is a factor of n(n + 1)(n + 2).
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- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
9. Sequences, Series, & Induction
Sequences
Problem 33
Textbook Question
Use mathematical induction to prove that each statement is true for every positive integer n. (ab)n = an bn
Verified step by step guidance1
Step 1: **State the proposition** you want to prove using mathematical induction. Let \( P(n) \) be the statement \( (ab)^n = a^n b^n \) for a positive integer \( n \).
Step 2: **Base case:** Verify that \( P(1) \) is true. Substitute \( n = 1 \) into the statement to check if \( (ab)^1 = a^1 b^1 \) holds.
Step 3: **Inductive hypothesis:** Assume that \( P(k) \) is true for some positive integer \( k \), i.e., assume \( (ab)^k = a^k b^k \).
Step 4: **Inductive step:** Use the inductive hypothesis to prove that \( P(k+1) \) is true. Start with \( (ab)^{k+1} = (ab)^k (ab) \) and then substitute the inductive hypothesis to rewrite it as \( a^k b^k (ab) \).
Step 5: **Simplify the expression** from Step 4 by using the associative and commutative properties of multiplication to show that \( a^k b^k (ab) = a^{k+1} b^{k+1} \), thus proving \( P(k+1) \). Conclude that by mathematical induction, the statement is true for all positive integers \( n \).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Mathematical Induction
Mathematical induction is a proof technique used to establish that a statement holds for all positive integers. It involves two steps: proving the base case (usually n=1) is true, and then proving that if the statement holds for an arbitrary integer k, it also holds for k+1. This creates a chain of truth for all n.
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Properties of Exponents
The properties of exponents describe how to manipulate expressions involving powers. One key property is that (ab)^n = a^n * b^n, meaning the nth power of a product equals the product of the nth powers. Understanding this property is essential to prove the given statement using induction.
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Algebraic Manipulation
Algebraic manipulation involves rearranging and simplifying expressions using algebraic rules. In this proof, it is necessary to rewrite (ab)^(k+1) as (ab)^k * (ab) and then apply the induction hypothesis and exponent rules to show equality. Mastery of these skills helps in constructing clear and logical proofs.
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