In Exercises 36–38, begin by graphing f(x) = log2 x Then use transformations of this graph to graph the given function. What is the graph's x-intercept? What is the vertical asymptote? Use the graphs to determine each function's domain and range. g(x) = log2 (x-2)
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
6. Exponential & Logarithmic Functions
Introduction to Logarithms
Problem 39
Textbook Question
Evaluate each expression without using a calculator. log5 57
Verified step by step guidance1
Recognize that the expression is \( \log_5 5^7 \), which is a logarithm with base 5 of \( 5^7 \).
Recall the logarithmic identity: \( \log_b b^x = x \), which means the logarithm of a base raised to a power is just the exponent.
Apply this identity directly to the expression: \( \log_5 5^7 = 7 \).
Therefore, the value of \( \log_5 5^7 \) simplifies to the exponent 7 without further calculation.
This shows how logarithms and exponents are inverse operations, making such expressions straightforward to evaluate.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Logarithm Definition
A logarithm answers the question: to what exponent must the base be raised to produce a given number? For example, log_b(a) = c means b^c = a. Understanding this definition is essential for evaluating logarithmic expressions.
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Logarithm of a Power
The logarithm of a number raised to an exponent can be simplified using the rule log_b(a^c) = c * log_b(a). This property allows you to bring the exponent in front as a multiplier, simplifying the evaluation process.
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Logarithm of the Base
When the argument of a logarithm is the same as its base, log_b(b) equals 1 because b^1 = b. This fact helps simplify expressions like log5(5^7) by reducing the inner logarithm to a simple exponent.
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