In Exercises 77–92, use the graph to determine a.the x-intercepts, if any; b. the y-intercept, if any; and e. the missing function values, indicated by question marks, below each graph.
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- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
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- 10. Combinatorics & Probability1h 45m
3. Functions
Intro to Functions & Their Graphs
Problem 61
Textbook Question
Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. x² + y² − x + 2y + 1 = 0
Verified step by step guidance1
Start with the given equation: \(x^{2} + y^{2} - x + 2y + 1 = 0\).
Group the \(x\) terms and \(y\) terms together: \((x^{2} - x) + (y^{2} + 2y) = -1\) (move the constant term to the right side).
Complete the square for the \(x\) terms: take half of the coefficient of \(x\) (which is \(-1\)), square it, and add inside the parentheses. Half of \(-1\) is \(-\frac{1}{2}\), and its square is \(\left(-\frac{1}{2}\right)^2 = \frac{1}{4}\). Do the same for the \(y\) terms: half of \$2\( is \)1\(, and its square is \)1^2 = 1$.
Add these squares to both sides of the equation to keep it balanced: \((x^{2} - x + \frac{1}{4}) + (y^{2} + 2y + 1) = -1 + \frac{1}{4} + 1\).
Rewrite each perfect square trinomial as a squared binomial: \((x - \frac{1}{2})^{2} + (y + 1)^{2} = \text{(simplify the right side)}\). This is the standard form of a circle equation, where the center is at \(\left(\frac{1}{2}, -1\right)\) and the radius is the square root of the right side.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Completing the Square
Completing the square is a method used to rewrite quadratic expressions in the form (x - h)² or (y - k)² by adding and subtracting appropriate constants. This technique helps transform the general form of a circle's equation into its standard form, making it easier to identify key features like the center and radius.
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Solving Quadratic Equations by Completing the Square
Standard Form of a Circle's Equation
The standard form of a circle's equation is (x - h)² + (y - k)² = r², where (h, k) represents the center and r is the radius. Writing the equation in this form allows for straightforward identification of the circle's geometric properties and simplifies graphing.
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Circles in Standard Form
Identifying the Center and Radius from the Equation
Once the equation is in standard form, the center of the circle is given by the coordinates (h, k), and the radius is the square root of the constant on the right side. Understanding how to extract these values is essential for graphing the circle accurately and interpreting its position and size.
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Circles in Standard Form
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