Find all values of x satisfying the given conditions. y1 = - x2 + 4x - 2, y2 = - 3x2 + x - 1, and y1 - y2 = 0
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Intro to Quadratic Equations
Problem 20a
Textbook Question
Use specific values for x and y to show that, in general, 1/x + 1/y is not equivalent to 1 / x + y.
Verified step by step guidance1
Start by choosing specific values for \( x \) and \( y \). For example, let \( x = 2 \) and \( y = 3 \).
Calculate the left side of the expression: \( \frac{1}{x} + \frac{1}{y} \). Substitute the values to get \( \frac{1}{2} + \frac{1}{3} \).
Calculate the right side of the expression: \( \frac{1}{x + y} \). Substitute the values to get \( \frac{1}{2 + 3} = \frac{1}{5} \).
Simplify the left side by finding a common denominator: \( \frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6} \).
Compare the two results: \( \frac{5}{6} \) (left side) and \( \frac{1}{5} \) (right side). Since these are not equal, this shows that \( \frac{1}{x} + \frac{1}{y} \) is not equivalent to \( \frac{1}{x + y} \) in general.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Properties of Fractions and Addition
Understanding how fractions are added is essential. When adding fractions like 1/x and 1/y, you must find a common denominator, resulting in (y + x) / (xy), which differs from simply adding denominators. This highlights that fraction addition is not the same as adding denominators directly.
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Substitution of Specific Values
Using specific numerical values for variables helps verify or disprove algebraic equivalences. By substituting numbers for x and y, you can compute both expressions and compare results, demonstrating whether the expressions are equivalent or not.
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Algebraic Expression Equivalence
Two algebraic expressions are equivalent if they yield the same value for all permissible variable values. Showing that 1/x + 1/y differs from 1/(x + y) for some values of x and y proves they are not equivalent expressions.
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