Find all values of x satisfying the given conditions. y = 2x2 - 3x and y = 2
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Intro to Quadratic Equations
Problem 125
Textbook Question
When the sum of 6 and twice a positive number is subtracted from the square of the number, 0 results. Find the number.
Verified step by step guidance1
Let the positive number be represented by the variable x.
Translate the problem into an equation: The square of the number is x², twice the number is 2x, and the sum of 6 and twice the number is 6 + 2x. Subtracting this from the square of the number gives the equation x² - (6 + 2x) = 0.
Simplify the equation by distributing the negative sign: x² - 6 - 2x = 0.
Rearrange the equation into standard quadratic form: x² - 2x - 6 = 0.
Solve the quadratic equation x² - 2x - 6 = 0 using the quadratic formula x = (-b ± √(b² - 4ac)) / 2a, where a = 1, b = -2, and c = -6. Simplify the discriminant and solve for x, ensuring to only consider the positive solution since the problem specifies a positive number.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, variables, and operations. In this problem, we need to translate the verbal statement into an algebraic expression, which involves identifying the positive number as a variable and expressing the relationships described in the question using algebraic notation.
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Quadratic Equations
A quadratic equation is a polynomial equation of the form ax² + bx + c = 0, where a, b, and c are constants. The problem leads us to form a quadratic equation by setting the expression derived from the problem equal to zero, allowing us to find the value of the variable that satisfies the equation.
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Solving for Variables
Solving for variables involves finding the value of the unknown that makes the equation true. This can be done through various methods such as factoring, using the quadratic formula, or completing the square. In this case, once we have the quadratic equation, we will apply one of these methods to determine the positive number that meets the conditions of the problem.
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