Find all values of x such that y = 0. y = 1/(5x + 5) - 3/(x + 1) + 7/5
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Rational Equations
Problem 37
Textbook Question
Solve each equation with rational exponents in Exercises 31–40. Check all proposed solutions. (x - 4)2/3 = 16
Verified step by step guidance1
Recognize that the equation involves a rational exponent: \( (x - 4)^{\frac{2}{3}} = 16 \). The exponent \(\frac{2}{3}\) means we first take the cube root of \(x - 4\) and then square the result.
To eliminate the rational exponent, raise both sides of the equation to the reciprocal power, which is \(\frac{3}{2}\). This gives: \(\left((x - 4)^{\frac{2}{3}}\right)^{\frac{3}{2}} = 16^{\frac{3}{2}}\).
Simplify the left side using the property of exponents \(\left(a^{m}\right)^{n} = a^{mn}\), so the left side becomes \(x - 4\). The equation now is \(x - 4 = 16^{\frac{3}{2}}\).
Evaluate \$16^{\frac{3}{2}}\( by first finding the square root of 16, which is 4, and then raising 4 to the 3rd power, which is \)4^3$. This gives the right side value.
Solve for \(x\) by adding 4 to both sides: \(x = 16^{\frac{3}{2}} + 4\). Finally, check all proposed solutions by substituting them back into the original equation to ensure they satisfy it.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Rational Exponents
Rational exponents represent roots and powers combined; for example, an exponent of m/n means taking the nth root and then raising to the mth power. Understanding how to manipulate expressions with rational exponents is essential for solving equations like (x - 4)^(2/3) = 16.
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Isolating the Variable
To solve equations, isolate the term containing the variable by undoing operations step-by-step. For rational exponents, this often involves raising both sides of the equation to the reciprocal power to eliminate the exponent and solve for the variable.
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Checking Solutions
After solving, substitute proposed solutions back into the original equation to verify they satisfy it. This is crucial when dealing with rational exponents, as raising to even roots can introduce extraneous solutions that do not satisfy the original equation.
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