Use the various properties of exponential and logarithmic functions to evaluate the expressions in parts (a)–(c). Given g(x) = ex, find g(ln 4)
Ch. 4 - Inverse, Exponential, and Logarithmic Functions

Chapter 5, Problem 95
Solve each equation. See Examples 4–6. 1/27 = x-3
Verified step by step guidance1
Start with the given equation: \(\frac{1}{27} = x^{-3}\).
Recall that a negative exponent means the reciprocal, so rewrite \(x^{-3}\) as \(\frac{1}{x^3}\), giving \(\frac{1}{27} = \frac{1}{x^3}\).
Since the fractions are equal and both have numerator 1, set the denominators equal: \$27 = x^3$.
To solve for \(x\), take the cube root of both sides: \(x = \sqrt[3]{27}\).
Simplify the cube root to find the value of \(x\).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Negative Exponents
A negative exponent indicates the reciprocal of the base raised to the corresponding positive exponent. For example, x^(-n) equals 1 divided by x^n. Understanding this allows rewriting expressions like x^-3 as 1/x^3.
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Zero and Negative Rules
Properties of Exponents
Exponent rules, such as a^(m) * a^(n) = a^(m+n) and (a^m)^n = a^(m*n), help simplify and solve equations involving powers. Applying these properties enables manipulation of expressions to isolate variables.
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Rational Exponents
Solving Exponential Equations
Solving equations with variables in exponents often involves rewriting both sides with the same base or using logarithms. In this problem, expressing both sides as powers of 3 allows equating exponents to find x.
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Solving Exponential Equations Using Logs
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