A simple random sample of size kk is drawn from a very large population with population mean MM and population standard deviation SS. What are the mean and standard deviation of the sampling distribution of the sample mean Yˉ\bar{Y}?

μYˉ=M\mu_{\bar{Y}}=MσYˉ=Sk\sigma_{\bar{Y}}=\dfrac{S}{\sqrt{k}}

μYˉ=M\mu_{\bar{Y}}=MσYˉ=Sk\sigma_{\bar{Y}}=\dfrac{S}{k}

μYˉ=Mk\mu_{\bar{Y}}=\dfrac{M}{k}σYˉ=Sk\sigma_{\bar{Y}}=\dfrac{S}{k}

μYˉ=Mk\mu_{\bar{Y}}=\dfrac{M}{\sqrt{k}}σYˉ=Sk\sigma_{\bar{Y}}=\dfrac{S}{\sqrt{k}}

A simple random sample of size kk is drawn from a very large popu...

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Sampling Distribution of the Sample Mean and Central Limit Theorem: Videos & Practice Problems

A simple random sample of size kk is drawn from a very large population with population mean MM and population standard deviation SS. What are the mean and standard deviation of the sampling distribution of the sample mean Yˉ\(\bar{Y}\)?

A simple random sample of size $k$ is drawn from a very large population with population mean $M$ and population standard deviation $S$ . What are the mean and standard deviation of the sampling distribution of the sample mean $\overset{ˉ}{Y}$ ?