A study analyzed the variation in reaction times (in $$seconds^{2}) $$for a sample of 77 individuals. The sample variance was found to be 0.640.64. Assume the data come from a normally distributed population. Construct the 99%99\% confidence interval for the population variance and the population standard deviation.

For variance: (0.21,5.68)(0.21,5.68) For standard deviation: (0.46,2.38)(0.46,2.38)

For variance: (0.17,4.75)(0.17,4.75)For standard deviation: (0.48,2.10)(0.48,2.10)

For variance: (0.18,4.40)(0.18,4.40)For standard deviation: (0.34,3.09)(0.34,3.09)

For variance: (0.28,4.11)(0.28,4.11)For standard deviation: (0.56,2.88)(0.56,2.88)

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Problem 89Multiple Choice

A study analyzed the variation in reaction times (in seconds²) for a sample of $7$ individuals. The sample variance was found to be $0.64$ . Assume the data come from a normally distributed population. Construct the $99 percent sign$ confidence interval for the population variance and the population standard deviation.

For variance: $open paren 0.17 comma 4.75 close paren$

For standard deviation: $open paren 0.48 comma 2.10 close paren$

For variance: $open paren 0.18 comma 4.40 close paren$

For standard deviation: $open paren 0.34 comma 3.09 close paren$

For variance: $open paren 0.21 comma 5.68 close paren$

For standard deviation: $open paren 0.46 comma 2.38 close paren$

For variance: $open paren 0.28 comma 4.11 close paren$

For standard deviation: $open paren 0.56 comma 2.88 close paren$

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