In Exercises 1–38, solve each radical equation._____√2x + 1 = x - 7
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Step 1: Isolate the square root on one side of the equation. The equation is already in the form \( \sqrt{2x + 1} = x - 7 \).
Step 2: Square both sides of the equation to eliminate the square root. This gives \( (\sqrt{2x + 1})^2 = (x - 7)^2 \).
Step 3: Simplify both sides. The left side becomes \( 2x + 1 \), and the right side becomes \( x^2 - 14x + 49 \).
Step 4: Rearrange the equation to form a quadratic equation. Move all terms to one side: \( x^2 - 14x + 49 - 2x - 1 = 0 \).
Step 5: Simplify the quadratic equation to \( x^2 - 16x + 48 = 0 \) and solve for \( x \) using the quadratic formula or by factoring.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Radical Equations
Radical equations are equations that involve a variable within a radical (square root, cube root, etc.). To solve these equations, one typically isolates the radical on one side and then squares both sides to eliminate the radical. This process may introduce extraneous solutions, so it's essential to check all potential solutions in the original equation.
Isolating the variable is a fundamental algebraic technique used to solve equations. This involves rearranging the equation to get the variable on one side and all other terms on the opposite side. In the context of radical equations, isolating the radical before squaring both sides is crucial for correctly solving the equation.
Extraneous solutions are solutions that emerge from the process of solving an equation but do not satisfy the original equation. This often occurs when squaring both sides of a radical equation. It is important to substitute any found solutions back into the original equation to verify their validity and ensure they are not extraneous.