In Exercises 27–62, graph the solution set of each system of ineq...

Question

In Exercises 27–62, graph the solution set of each system of inequalities or indicate that the system has no solution. 3x+6y≤6, 2x+y≤8

Accepted Answer

Consider the following system of inequalities two X plus four, Y is less than equal to eight and four, X plus Y is less than equal to four. Now, I want to graph the solution set so this will be the shaded region that qualifies both of our inequalities. We look here, our first line to expose for Y is less than equals. Eight is denoted by the green line, which is right here. So we shared everything below that in this case. Similarly for X plus Y is less or equal to four is shown by the purple line, which will shade everything below again. So you want the area where both shaded regions overlap. We notice here, this is right around this area where both regions are overlapping. That's so we can find the graph that has this shaded area. See graphic A does not look like the same shaded area. Graff and graff. C. Does not, and d is no solution, which we can tell there is a solution. We can tell them that our solution is graph Beak. Okay, I hope to help you solve the problem. Thank you for watching. Goodbye

In Exercises 27–62, graph the solution set of each system of inequalities or indicate that the system has no solution. 3x+6y≤6, 2x+y≤8

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