Solve each rational inequality in Exercises 43–60 and graph the solution set on a real number line. Express each solution set in interval notation. (x - 2)/(x + 2) ≤ 2
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Step 1: Start by rewriting the inequality \( \frac{x - 2}{x + 2} \leq 2 \) in a form that can be solved. Subtract 2 from both sides to get \( \frac{x - 2}{x + 2} - 2 \leq 0 \).
Step 2: Combine the terms on the left-hand side over a common denominator: \( \frac{x - 2 - 2(x + 2)}{x + 2} \leq 0 \). Simplify the numerator to get \( \frac{x - 2 - 2x - 4}{x + 2} \leq 0 \).
Step 4: Identify the critical points by setting the numerator and denominator equal to zero: \(-x - 6 = 0\) and \(x + 2 = 0\). Solve these equations to find the critical points \(x = -6\) and \(x = -2\).
Step 5: Use the critical points to test intervals on the number line: \((-\infty, -6)\), \((-6, -2)\), and \((-2, \infty)\). Determine where the inequality holds true and express the solution set in interval notation.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Rational Inequalities
Rational inequalities involve expressions that are ratios of polynomials set in relation to an inequality sign. To solve them, one typically finds critical points by setting the numerator and denominator to zero, which helps identify intervals to test for the inequality's truth. Understanding how to manipulate and analyze these expressions is crucial for finding valid solutions.
Interval notation is a mathematical notation used to represent a range of values on the real number line. It uses parentheses and brackets to indicate whether endpoints are included (closed intervals) or excluded (open intervals). Mastery of interval notation is essential for clearly expressing the solution set of inequalities.
Graphing solutions on a number line visually represents the solution set of an inequality. This involves marking critical points and shading the appropriate regions to indicate where the inequality holds true. Understanding how to accurately graph these solutions aids in comprehending the behavior of the inequality across different intervals.