Multiple ChoiceWrite the given quadratic equation in standard form. Identify a, b, and c. −4x2+x=8-4x^2+x=8−4x2+x=8241views2rank
Multiple ChoiceSolve the given quadratic equation by factoring. 3x2+12x=03x^2+12x=03x2+12x=0205views2comments
Textbook QuestionMatch the equation in Column I with its solution(s) in Column II. x^2 - 5 = 0161views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Which equation is set up for direct use of the zero-factor property? Solve it225views
Textbook QuestionAnswer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. Find two consecutive integers whose product is 110.447views1rank
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. Find two consecutive even integers whose product is 168.166views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Only one of the equations does not require Step 1 of the method for completing the square described in this section. Which one is it? Solve it.175views
Textbook QuestionUse Choices A–D to answer each question. A. 3x^2 - 17x - 6 = 0 B. (2x + 5)^2 = 7 C. x^2 + x = 12 D. (3x - 1)(x - 7) = 0 Only one of the equations is set up so that the values of a, b, and c can be determined immediately. Which one is it? Solve it.163views
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. The sum of the squares of two consecutive odd integers is 202. Find the integers184views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 3x^2 = 27319views
Textbook QuestionAnswer each question. Answer each question. Answer each question. Unknown NumbersUse the following facts.If x represents an integer, then x+1 represents the next consecutive integer.If x represents an even integer, then x+2 represents the next consecutive even integer.If x represents an odd integer, then x+2 represents the next consecutive odd integer. The sum of the squares of two consecutive even integers is 52. Find the integers.176views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 5x^2 = 45283views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 2x^2 - x = 15200views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. -6x^2 + 7x = -10212views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 3x^2 - 1 = 47371views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. 2x^2 - 5 = - 55203views
Textbook QuestionSolve each problem. See Examples 1 and 2. Dimensions of a Square. The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in.2. Find the lengths of the sides of the two squares.340views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 9x^2 - 12x + 4 = 0262views
Textbook QuestionSolve each problem. See Examples 1. Dimensions of a Parking Lot. A parking lot has a rectangular area of 40,000 yd2. The length is 200 yd more than twice the width. Find the dimensions of the lot.193views
Textbook QuestionSolve each equation using the zero-factor property. See Example 1. 36x^2 + 60x + 25 = 0156views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (x - 3)^2 = - 5281views
Textbook QuestionSolve each equation using the square root property. See Example 2. 48 - x^2 = 0254views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (3x + 2)^2 = 9161views
Textbook QuestionManufacturing to Specifications. A manufacturing firm wants to package its product in a cylindrical container 3 ft high with surface area 8π ft2. What should the radius of the circular top and bottom of the container be? (Hint: The surface area consists of the circular top and bottom and a rectangle that represents the side cut open vertically and unrolled.)187views
Textbook QuestionSolve each equation using the square root property. See Example 2. x^2 = -400236views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (4x - 1)^2 = 16198views
Textbook QuestionSolve each equation in Exercises 15–34 by the square root property. (8x - 3)^2 = 5187views
Textbook QuestionRadius of a CanA can of Blue Runner Red Kidney Beans has surface area 371 cm^2. Its height is 12 cm. What is the radius of the circular top? Round to the nearest hun-dredth.237views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. x^2 - 7x + 12 = 0156views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 + 3x406views
Textbook QuestionSolve each problem. See Example 2. Length of a WalkwayA nature conservancy group decides to construct a raised wooden walkway through a wetland area. To enclose the most interesting part of the wetlands, the walkway will have the shape of a right triangle with one leg 700 yd longer than the other and the hypotenuse 100 yd longer than the longer leg. Find the total length of the walkway.202views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - 7x315views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. x^2 - 2x - 2 = 0361views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. 2x^2 + x = 10212views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - (2/3)x324views
Textbook QuestionIn Exercises 35–46, determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the trinomial. x^2 - (1/3)x325views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. -3x^2 + 6x + 5 = 0172views
Textbook QuestionWhich equation has two real, distinct solutions? Do not actually solve. A. (3x-4)² = -9 B. (4-7x)² = 0 C. (5x-9)(5x-9) = 0 D. (7x+4)² = 11195views
Textbook QuestionSolve each equation using completing the square. See Examples 3 and 4. 3x^2 - 9x + 7 = 0323views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 - x - 1 = 0196views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 - 6x - 11 = 0218views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number and type of solutions. 16x² +3 = -26x135views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 + 4x + 1 = 0253views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 - 6x = -7201views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. x^2 = 2x - 5177views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 - 5x + 6 = 0196views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. x^2 + 3x - 1 = 0178views
Textbook QuestionSolve each problem. Dimensions of a Right TriangleThe shortest side of a right triangle is 7 in. shorter than the middle side, while the longest side (the hypot-enuse) is 1 in. longer than the middle side. Find the lengths of the sides.146views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. 2/3x^2 + 1/4x = 3236views
Textbook QuestionSolve each equation using the quadratic formula. See Examples 5 and 6. (4x - 1)(x + 2) = 4x302views
Textbook QuestionSolve each equation in Exercises 47–64 by completing the square. 3x^2 - 5x - 10 = 0295views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. x^2 + 8x + 15 = 0224views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. x^2 + 5x + 3 = 0637views
Textbook QuestionSolve each cubic equation using factoring and the quadratic formula. See Example 7. x^3 - 27 = 0419views
Textbook QuestionSolve each equation in Exercises 65–74 using the quadratic formula. 3x^2 - 3x - 4 = 0257views
Textbook QuestionSolve each cubic equation using factoring and the quadratic formula. See Example 7. x^3 + 64 = 0262views
Textbook QuestionSolve each equation in Exercises 68–70 using the quadratic formula. 2x^2 = 3-4x273views
Textbook QuestionIn Exercises 71–72, without solving the given quadratic equation, determine the number and type of solutions. 9x^2 = 2-3x322views
Textbook QuestionSolve each equation in Exercises 73–81 by the method of your choice. 3x^2-7x+1 =0196views
Textbook QuestionSolve each equation for the specified variable. (Assume no denominators are 0.) See Example 8. r = r_0+(1/2)at^2, for t180views
Textbook QuestionSolve each equation in Exercises 73–81 by the method of your choice. (x-3)^2 - 25 = 0253views
Textbook QuestionSolve each equation for the specified variable. (Assume no denominators are 0.) See Example 8. h = -16t^2+v_0t+s_0, for t173views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. 2x^2 - 11x + 3 = 0230views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. x^2 - 2x + 1 = 0210views
Textbook QuestionFor each equation, (b) solve for y in terms of x. See Example 8. 4x^2 - 2xy + 3y^2 = 2291views
Textbook QuestionFor each equation, (a) solve for x in terms of y. See Example 8. 2x^2 + 4xy - 3y^2 = 2159views
Textbook QuestionIn Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. x^2 - 3x - 7 = 0303views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 2x^2 - x = 1229views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 3x^2 + 5x + 2 = 0177views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 4x^2 = -6x + 3290views
Textbook QuestionEvaluate the discriminant for each equation. Then use it to determine the number of distinct solutions, and tell whether they are rational, irrational, or nonreal complex numbers. (Do not solve the equation.) See Example 9. 8x^2 - 72 = 0229views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (2x + 3)(x + 4) = 1270views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (2x - 5)(x + 1) = 2189views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. (3x - 4)^2 = 16183views
Textbook QuestionAnswer each question. Find the values of a, b, and c for which the quadratic equation. ax^2 + bx + c = 0 has the given numbers as solutions. (Hint: Use the zero-factor property in reverse.) 4, 5350views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 3x^2 - 12x + 12 = 0239views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. x^2 - 4x + 29 = 0193views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. x^2 = 4x - 7191views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 2x^2 - 7x = 0184views
Textbook QuestionSolve each equation in Exercises 83–108 by the method of your choice. 1/x + 1/(x + 2) = 1/3219views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = x^2 - 4x - 5200views
Textbook QuestionIn Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = - (x + 1)^2 + 4300views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y = 2x^2 - 3x and y = 2298views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y = 5x^2 + 3x and y = 2224views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y1 = 2x^2 + 5x - 4, y2 = - x^2 + 15x - 10, and y1 - y2 = 0311views
Textbook QuestionIn Exercises 115–122, find all values of x satisfying the given conditions. y1 = - x^2 + 4x - 2, y2 = - 3x^2 + x - 1, and y1 - y2 = 0299views
Textbook QuestionWhen the sum of 6 and twice a positive number is subtracted from the square of the number, 0 results. Find the number.234views
Textbook QuestionWhen the sum of 1 and twice a negative number is subtracted from twice the square of the number, 0 results. Find the number.202views