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Multiple Choice
Factor completely.
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1
Identify the quadratic expression to factor: \(2x^{2} + 9x + 9\).
Multiply the coefficient of \(x^{2}\) (which is 2) by the constant term (which is 9) to get \(2 \times 9 = 18\).
Find two numbers that multiply to 18 and add up to the middle coefficient, 9. These numbers are 6 and 3 because \(6 \times 3 = 18\) and \(6 + 3 = 9\).
Rewrite the middle term \$9x$ as \(6x + 3x\), so the expression becomes \(2x^{2} + 6x + 3x + 9\).
Group the terms in pairs and factor each group: from the first two terms, factor out \$2x\( to get \(2x(x + 3)\); from the last two terms, factor out 3 to get \(3(x + 3)\). Then factor out the common binomial \)(x + 3)\( to get \)(2x + 3)(x + 3)$.