An objective function and a system of linear inequalities representing constraints are given. a. Graph the system of inequalities representing the constraints. b. Find the value of the objective function at each corner of the graphed region. c. Use the values in part (b) to determine the maximum value of the objective function and the values of x and y for which the maximum occurs.
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
7. Systems of Equations & Matrices
Graphing Systems of Inequalities
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Graph the inequality 2x+3y < 6.
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Verified step by step guidance1
Start by rewriting the inequality 2x + 3y < 6 in slope-intercept form (y = mx + b). To do this, solve for y: 3y < -2x + 6.
Divide every term by 3 to isolate y: y < -2/3x + 2. This is the equation of the boundary line, but since the inequality is '<', the line will be dashed, indicating that points on the line are not included in the solution.
Identify the slope and y-intercept from the equation y = -2/3x + 2. The slope (m) is -2/3, and the y-intercept (b) is 2.
Plot the y-intercept (0, 2) on the graph. From this point, use the slope to find another point: move down 2 units and right 3 units to plot the second point.
Draw a dashed line through these points to represent the boundary. Since the inequality is '<', shade the region below the line, which represents all the points (x, y) that satisfy the inequality 2x + 3y < 6.
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Graphing Systems of Inequalities practice set

