Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
2. Graphs of Equations
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Problem 34
Textbook Question
In Exercises 33–34, find and simplify the difference quotient [f(x + h) - f(x)]/h, h =/= 0 for the given function. f(x) = -2x^2 + x + 10
Verified step by step guidance1
Step 1: Start by substituting (x + h) into the function f(x). The function is f(x) = -2x^2 + x + 10, so f(x + h) becomes f(x + h) = -2(x + h)^2 + (x + h) + 10.
Step 2: Expand the expression for f(x + h). Use the distributive property to expand (x + h)^2, which gives x^2 + 2xh + h^2. Substituting this back, f(x + h) = -2(x^2 + 2xh + h^2) + x + h + 10.
Step 3: Simplify f(x + h) by distributing -2 and combining like terms. This results in f(x + h) = -2x^2 - 4xh - 2h^2 + x + h + 10.
Step 4: Compute the difference f(x + h) - f(x). Subtract f(x) = -2x^2 + x + 10 from the expanded f(x + h). This gives [-2x^2 - 4xh - 2h^2 + x + h + 10] - [-2x^2 + x + 10].
Step 5: Simplify the numerator of the difference quotient by canceling out terms and combining like terms. Then divide the simplified numerator by h (noting that h ≠ 0). The final expression will be the simplified form of the difference quotient.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Difference Quotient
The difference quotient is a formula used to calculate the average rate of change of a function over an interval. It is expressed as [f(x + h) - f(x)]/h, where h represents a small change in x. This concept is fundamental in calculus as it leads to the derivative, which measures the instantaneous rate of change.
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Function Evaluation
Function evaluation involves substituting a specific value into a function to determine its output. In the context of the difference quotient, you need to evaluate the function f at both x and x + h. This step is crucial for calculating the difference quotient accurately and understanding how the function behaves as x changes.
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Simplification of Expressions
Simplification of expressions is the process of reducing a mathematical expression to its simplest form. This often involves combining like terms, factoring, or canceling common factors. In the context of the difference quotient, simplifying the resulting expression after substituting into the formula is essential for finding a clear and concise representation of the average rate of change.
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Find the slope and y-intercept of each line, and graph it. 4x-y =7
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