Measuring Absorbance - Video Tutorials & Practice Problems

Measuring Absorbance

1

example

Measuring Absorbance Calculations 1

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So here it says in UV vis spectroscopy, the absorbent represents the quantity of light that a sample absorbs while the percent trans mittens represents the amount of light that passes through a sample calculate the percent transmits of a substance if its absorbency is measured as 0.419. But we need to realize here is that absorb ints and percent transmit mints are basically opposites of enough of one another. If you are absorbing 100% of light by the substance that means there is 0% of trans mittens that's going on. And then conversely if you are transmitting 100% that means that 0% of light is being absorbed. Okay so they kind of work against each other here we're going to say that percent transmitting. So um percent t equals your anti log 2 to the -, absorb its. Okay so that's the formula we use in order to determine what our transmits will be. So then what we're gonna say here is we're gonna say 10 To the to -119. So that's going to equal here 10 to the 1.581. So then when we punch that in we're gonna get here 38.1. So that represents 38.1%. So that means that we're going to have 38.1% of light passing through the sample which means that the remainder of 100% is being absorbed by that sample. So you'd say absorb ints would be just 100% minus that number. Remember they're opposites of one another. If one is doing its job 100% The other one would be 0% and you gotta find a way of balancing the two. In terms of your sample itself, the more concentrated your sample becomes, the harder it is for light to pass through it, so the more it'll absorb light Since we've done that one. Move on to the next question. Here we say. If your percent, transmissions is 39.1% determine the absorbent. Pretty straightforward. We're going the opposite way. See if you can manipulate this equation to get the desired equation to figure out your absorbent.

2

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Measuring Absorbance Calculations 1

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1m

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So here we just have to manipulate the original equation given to us to fit the situation to help us find absorbent. So percent transmit mints Equals 10 to the two -A. Here. To get rid of anti log. I'm gonna do the log of both sides so that's gonna become log of percent T. Here. This is anti log, this is log when there are next to each other. They basically cancel one another out. Leaving behind the power which comes down so it's gonna become two -A. So track two from both sides here. So log % T -2 equals negative a Divide both sides by -1. So then that's gonna give us negative log t minus um Plus two equals A. So just plug in the value that we have Plus two which will give me a when you punch that in. We get .408 for my absorbent. So just remember the connection between absorbent and percent transmit. Since now that we've seen this handle the practice question that's left on the bottom, we have to identify the colors of a compound if it's absorbing the given colors here to help us were provided with the color wheel. See if you can use the color wheel to figure out the answer would be

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Problem

Problem

Identify the colors of a compound that absorbs green light, yellow-green light and blue light.