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Multiple Choice
State the order of the differential equation and indicate if it is linear or nonlinear.
(y′′)2+6ety′=4t
A
2nd order, linear
B
2nd order, nonlinear
C
1st order, linear
D
1st order, nonlinear
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Verified step by step guidance
1
Step 1: Identify the highest derivative present in the given differential equation. The equation is \((y^{\prime\prime})^2 + 6e^t y^{\prime} = 4t\). The highest derivative is \(y^{\prime\prime}\), which is the second derivative of \(y\). Therefore, the equation is of second order.
Step 2: Determine if the equation is linear or nonlinear. A differential equation is linear if all terms involving the dependent variable \(y\) and its derivatives \(y^{\prime}, y^{\prime\prime}, \dots\) appear to the first power and are not multiplied together. In this equation, \((y^{\prime\prime})^2\) involves the second derivative squared, which makes the equation nonlinear.
Step 3: Verify the linearity condition for the remaining terms. The term \(6e^t y^{\prime}\) is linear because \(y^{\prime}\) appears to the first power and is not multiplied by another derivative or \(y\). However, the presence of \((y^{\prime\prime})^2\) overrides this and confirms nonlinearity.
Step 4: Summarize the findings. The equation is of second order because the highest derivative is \(y^{\prime\prime}\), and it is nonlinear because of the \((y^{\prime\prime})^2\) term.
Step 5: Conclude that the correct classification of the differential equation is: second order, nonlinear.