Match each statement with its corresponding graph in choices A–D. In each case, k > 0. y varies directly as the second power of x. (y=kx2)
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Rational Equations
Problem 37
Textbook Question
Current Flow In electric current flow, it is found that the resistance offered by a fixed length of wire of a given material varies inversely as the square of the diameter of the wire. If a wire 0.01 in. in diameter has a resistance of 0.4 ohm, what is the resistance of a wire of the same length and material with diameter 0.03 in., to the nearest ten-thousandth of an ohm?
Verified step by step guidance1
Identify the relationship given: resistance \( R \) varies inversely as the square of the diameter \( d \). This means we can write the equation as \( R = \frac{k}{d^2} \), where \( k \) is a constant.
Use the given values to find the constant \( k \). Substitute \( R = 0.4 \) ohms and \( d = 0.01 \) inches into the equation: \( 0.4 = \frac{k}{(0.01)^2} \).
Solve for \( k \) by multiplying both sides of the equation by \( (0.01)^2 \): \( k = 0.4 \times (0.01)^2 \).
Now, use the constant \( k \) to find the resistance \( R \) when the diameter \( d = 0.03 \) inches. Substitute into the formula: \( R = \frac{k}{(0.03)^2} \).
Calculate the value of \( R \) from the above expression and round it to the nearest ten-thousandth of an ohm.
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
2mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inverse Variation
Inverse variation describes a relationship where one quantity increases as another decreases, such that their product is constant. In this problem, resistance varies inversely as the square of the diameter, meaning resistance × (diameter)² = constant. Understanding this helps set up the equation to find unknown resistance.
Recommended video:
Graphing Logarithmic Functions
Setting Up and Solving Proportions
Proportions express equality between two ratios or fractions. Here, since resistance varies inversely with the square of diameter, you can set up a proportion comparing the known resistance and diameter squared to the unknown resistance and its diameter squared. Solving this proportion yields the desired resistance.
Recommended video:
Solving Logarithmic Equations
Rounding to a Specified Decimal Place
Rounding is the process of limiting a number to a certain number of decimal places for precision. The problem asks for the resistance rounded to the nearest ten-thousandth (four decimal places). Proper rounding ensures the final answer is both accurate and appropriately precise.
Recommended video:
The Number e
Watch next
Master Introduction to Rational Equations with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Textbook Question
524
views
