Identify the open intervals on which the function is increasing or decreasing.
$f(x)=x^{2/3}(4-x)$

• A. Decreasing on $\(\left\)(-\(\infty\),\(\infty\]\right\))$
• B. Increasing on $\(\left\)(-\(\infty\),\(\infty\]\right\))$
• C. Increasing on $\(\left\)(-\(\infty\),0\(\right\))\&\(\left\)(\(\frac\)85,\(\infty\]\right\))$, Decreasing on $\(\left\)(0,\(\frac\)85\(\right\))$
• D. Increasing on $\(\left\)(0,\(\frac\)85\(\right\))$, Decreasing on $\(\left\)(-\(\infty\),0\(\right\))\&\(\left\)(\(\frac\)85,\(\infty\]\right\))$

Answer: (D)

Verified step by step guidance

1. Step 1: Start by finding the derivative of the function f(x) = x^(2/3)(4 - x). Use the product rule for derivatives, which states that if f(x) = u(x)v(x), then f'(x) = u'(x)v(x) + u(x)v'(x). Here, u(x) = x^(2/3) and v(x) = (4 - x).
2. Step 2: Compute the derivative of u(x) = x^(2/3). Using the power rule, the derivative is u'(x) = (2/3)x^(-1/3). Next, compute the derivative of v(x) = (4 - x), which is v'(x) = -1.
3. Step 3: Substitute u'(x), u(x), v'(x), and v(x) into the product rule formula. This gives f'(x) = [(2/3)x^(-1/3)(4 - x)] + [x^(2/3)(-1)]. Simplify this expression to get the derivative in a usable form.
4. Step 4: Set f'(x) = 0 to find the critical points. Solve the equation [(2/3)x^(-1/3)(4 - x)] - x^(2/3) = 0. Factorize the expression to isolate x and determine the critical points.
5. Step 5: Use the critical points to test the intervals on the number line. Determine the sign of f'(x) in each interval to identify where the function is increasing (f'(x) > 0) or decreasing (f'(x) < 0). Based on this analysis, conclude the intervals of increase and decrease for the function.