Based on the previous example calculate the molarity value for each student if they dissolve 0.300 (± 0.03) moles of analyte.

1.5 ± 0.2 M for both

1.5 ± 0.2 M for student A and 1.5 ± 0.1 M for student B

1.5 ± 0.1 M for student A and 1.5 ± 0.2 M for student B

1.5 ± 0.04 M for student A and 1.5 ± 0.01 M for student B

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