Skip to main content
Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 3, Problem 3.1.63c

Another way to approximate derivatives is to use the centered difference quotient: f' (a) ≈ f(a+h) - f(a- h) / 2h. Again, consider f(x) = √x.
c. Explain why it is not necessary to use negative values of h in the table of part (b).

Verified step by step guidance
1
Step 1: Understand the centered difference quotient formula: The centered difference quotient is given by \( f'(a) \approx \frac{f(a+h) - f(a-h)}{2h} \). This formula is used to approximate the derivative of a function at a point \( a \).
Step 2: Recognize the role of \( h \): In the formula, \( h \) is a small positive number that represents a small change in \( x \). The choice of \( h \) affects the accuracy of the approximation.
Step 3: Consider symmetry in the formula: The centered difference quotient uses both \( f(a+h) \) and \( f(a-h) \), which means it inherently considers both positive and negative changes around \( a \).
Step 4: Analyze the effect of negative \( h \): Using a negative \( h \) would simply reverse the roles of \( f(a+h) \) and \( f(a-h) \), but since the formula already accounts for both directions, negative values of \( h \) are redundant.
Step 5: Conclude on the necessity of negative \( h \): Since the centered difference quotient already incorporates both forward and backward differences through its symmetric structure, using negative values of \( h \) does not provide additional information or improve the approximation.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Centered Difference Quotient

The centered difference quotient is a method for approximating the derivative of a function at a point by averaging the slopes of secant lines on either side of that point. It is defined as f'(a) ≈ (f(a+h) - f(a-h)) / (2h), where h is a small positive value. This approach provides a more accurate estimate of the derivative compared to the forward or backward difference quotients, especially when h is small.
Recommended video:
06:43
The Quotient Rule

Symmetry in Function Values

When using the centered difference quotient, the function values f(a+h) and f(a-h) are symmetrically located around the point a. This symmetry means that the contributions of positive and negative h values effectively cancel out any asymmetries in the function's behavior at a, allowing for a more accurate approximation of the derivative without needing to consider negative h values.
Recommended video:
06:37
Average Value of a Function

Behavior of the Function Near a Point

The behavior of the function f(x) near the point a is crucial for understanding why negative values of h are unnecessary. If the function is continuous and differentiable at a, the values of f(a+h) and f(a-h) will converge to the same limit as h approaches zero. Thus, using only positive h values suffices to capture the local behavior of the function around a, ensuring a reliable approximation of the derivative.
Recommended video:
04:50
Critical Points
Related Practice
Textbook Question

{Use of Tech} Power and energy Power and energy are often used interchangeably, but they are quite different. Energy is what makes matter move or heat up. It is measured in units of joules or Calories, where 1 Cal=4184 J. One hour of walking consumes roughly 10⁶J, or 240 Cal. On the other hand, power is the rate at which energy is used, which is measured in watts, where 1 W=1 J/s. Other useful units of power are kilowatts (1 kW=10³ W) and megawatts (1 MW=10⁶ W). If energy is used at a rate of 1 kW for one hour, the total amount of energy used is 1 kilowatt-hour (1 kWh=3.6×10⁶ J) Suppose the cumulative energy used in a large building over a 24-hr period is given by E(t)=100t+4t²−t³ / 9kWh where t=0 corresponds to midnight.

c. Graph the power function and interpret the graph. What are the units of power in this case?

215
views
Textbook Question

{Use of Tech} Spring runoff The flow of a small stream is monitored for 90 days between May 1 and August 1. The total water that flows past a gauging station is given by v(t) = <matrix 2x2> where V is measured in cubic feet and t is measured in days, with t=0 corresponding to May 1.

c. Describe the flow of the stream over the 3-month period. Specifically, when is the flow rate a maximum?

218
views
Textbook Question

62–65. {Use of Tech} Graphing f and f'

c. Verify that the zeros of f' correspond to points at which f has a horizontal tangent line.

f(x)=(sec^−1 x)/x on [1,∞)

219
views
Textbook Question

Derivatives from a graph If possible, evaluate the following derivatives using the graphs of f and f'. <IMAGE>

c. (f^-1)'(f(2))

382
views
Textbook Question

Highway travel A state patrol station is located on a straight north-south freeway. A patrol car leaves the station at 9:00 A.M. heading north with position function s = f(t) that gives its location in miles t hours after 9:00 A.M. (see figure). Assume s is positive when the car is north of the patrol station. <IMAGE>

c. Find the average velocity of the car over the interval [1.75, 2.25]. Estimate the velocity of the car at 11:00 A.M. and determine the direction in which the patrol car is moving.

239
views
Textbook Question

Suppose a stone is thrown vertically upward from the edge of a cliff on Earth with an initial velocity of 19.6 m/s from a height of 24.5 m above the ground. The height (in meters) of the stone above the ground t seconds after it is thrown is s(t) = -4.9t²+19.6t+24.5.

c. What is the height of the stone at the highest point?

183
views