Assume f is an odd function and that both f and g are one-to-one. Use the (incomplete) graph of f and the graph of g to find the following function values. <IMAGE>
f^-1(1 + f(-3))

Verified step by step guidance

1. Step 1: Understand the properties of odd functions. An odd function satisfies the condition f(-x) = -f(x) for all x in the domain of f.
2. Step 2: Use the property of odd functions to find f(-3). Since f is odd, f(-3) = -f(3).
3. Step 3: Calculate 1 + f(-3) using the result from Step 2. This becomes 1 - f(3).
4. Step 4: Understand the property of one-to-one functions. A function is one-to-one if it has an inverse, meaning each output is mapped from a unique input.
5. Step 5: Use the inverse function property to find f^{-1}(1 + f(-3)). Since 1 + f(-3) = 1 - f(3), find the x such that f(x) = 1 - f(3).

Key Concepts

Odd Functions

An odd function is defined by the property f(-x) = -f(x) for all x in its domain. This symmetry about the origin means that if you know the value of the function at a positive input, you can easily determine its value at the corresponding negative input. Understanding this property is crucial for evaluating expressions involving odd functions, such as f(-3) in the given question.

Inverse Functions

An inverse function, denoted as f^-1, reverses the effect of the original function. If f(x) = y, then f^-1(y) = x. For one-to-one functions, each output corresponds to exactly one input, allowing for the existence of an inverse. This concept is essential for solving the expression f^-1(1 + f(-3)), as it requires finding the input that produces a specific output.

One-to-One Functions

A one-to-one function is a function where each output is produced by exactly one input, meaning f(a) = f(b) implies a = b. This property ensures that the function has an inverse. In the context of the question, knowing that both f and g are one-to-one allows us to confidently use their inverses without ambiguity, which is critical for evaluating the function values requested.