Verify that the given value is a solution to the equation.
Table of contents
- 1. Review of Real Numbers1h 33m
- 2. Linear Equations and Inequalities2h 56m
- 3. Solving Word Problems1h 25m
- 4. Graphs and Functions2h 48m
- 5. Systems of Linear Equations1h 12m
- 7. Factoring1h 30m
- 8. Rational Expressions and Functions2h 21m
- 9. Roots, Radicals, and Complex Numbers2h 33m
- 10. Quadratic Equations and Functions1h 23m
- 11. Inverse, Exponential, & Logarithmic Functions1h 5m
- 12. Conic Sections & Systems of Nonlinear Equations58m
- 13. Sequences, Series, and the Binomial Theorem Coming soon
2. Linear Equations and Inequalities
Solving Linear Equations
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Solve the given linear equation using addition and subtraction properties of equality.
A
x=−13
B
x=13
C
x=3
D
x=−3
Verified step by step guidance1
Start with the given equation: \$2\left(x+5\right) = 3\left(x-1\right)$.
Apply the distributive property to both sides to eliminate the parentheses: multiply 2 by each term inside the first parentheses and 3 by each term inside the second parentheses, resulting in \$2x + 10 = 3x - 3$.
Use the addition and subtraction properties of equality to get all terms containing \(x\) on one side and constants on the other. For example, subtract \$2x\( from both sides to isolate \)x\( terms on one side: \)10 = 3x - 3 - 2x$.
Simplify the right side by combining like terms: \$10 = x - 3$.
Finally, add 3 to both sides to isolate \(x\): \$10 + 3 = x\(, which simplifies to \)x = 13$.
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