Solve the differential equation by separation of variables.
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- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
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- Logarithmic Functions24m
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- 1. Limits and Continuity2h 2m
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- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
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- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
13. Intro to Differential Equations
Basics of Differential Equations
Problem 9.1.46
Textbook Question
45–46. Harvesting problems Consider the harvesting problem in Example 6.
If r = 0.05 and H = 500, for what values of p₀ is the amount of the resource decreasing? For what value of p₀ is the amount of the resource constant? If p₀ = 9000, when does the resource vanish?
Verified step by step guidance1
Recall the harvesting model differential equation from Example 6, which is typically of the form: \[\frac{dp}{dt} = rp - H,\] where \(p(t)\) is the amount of the resource at time \(t\), \(r\) is the growth rate, and \(H\) is the harvesting rate.
To determine when the amount of the resource is decreasing, analyze the sign of \[\frac{dp}{dt} = rp - H.\] The resource decreases when \[\frac{dp}{dt} < 0,\] which means \[rp - H < 0.\] Solve this inequality for \(p\) to find the values of \(p_0\) (initial amount) where the resource decreases.
To find when the amount of the resource is constant, set \[\frac{dp}{dt} = 0,\] which gives \[rp - H = 0.\] Solve for \(p\) to find the equilibrium value of \(p_0\) where the resource neither increases nor decreases.
Given \(p_0 = 9000\), solve the differential equation \[\frac{dp}{dt} = rp - H\] with initial condition \(p(0) = 9000\) to find \(p(t)\). This is a first-order linear differential equation and can be solved using an integrating factor or separation of variables.
Once you have the explicit solution \(p(t)\), determine the time \(t\) when the resource vanishes by solving \[p(t) = 0\] for \(t\). This will give the time at which the resource is completely depleted.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Differential Equations in Population Dynamics
Differential equations model how populations change over time, incorporating growth and harvesting rates. In harvesting problems, the rate of change of the resource depends on natural growth minus the harvesting amount, allowing prediction of resource levels at any time.
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Classifying Differential Equations
Equilibrium Points and Stability
An equilibrium point occurs when the population remains constant over time, meaning growth equals harvesting. Determining the equilibrium helps identify values of the initial population where the resource neither grows nor declines, crucial for sustainable harvesting.
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Critical Points
Time to Extinction in Resource Models
Time to extinction refers to when the resource population reaches zero under given harvesting and growth rates. Solving the differential equation with initial conditions allows calculation of when the resource vanishes, important for managing resource depletion.
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Exponential Growth & Decay
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