Find the equations for the asymptotes of the hyperbola .
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
16. Parametric Equations & Polar Coordinates
Conic Sections
Problem 12.4.38
Textbook Question
31–38. Equations of parabolas Find an equation of the following parabolas. Unless otherwise specified, assume the vertex is at the origin.

Verified step by step guidance1
Identify the vertex of the parabola, which is given as (0, 2). This is the highest point on the parabola since it opens downward.
Note the directrix line, which is horizontal and given by the equation \(y = 4\). The parabola opens downward because the vertex is below the directrix.
Find the focus of the parabola. The focus lies the same distance from the vertex as the directrix but on the opposite side. Calculate the distance \(p\) between the vertex and the directrix: \(p = 4 - 2 = 2\). Since the parabola opens downward, the focus is at \((0, 2 - 2) = (0, 0)\).
Use the standard form of a vertical parabola with vertex \((h, k)\) and focus distance \(p\): \[(x - h)^2 = 4p(y - k)\]. Here, \(h = 0\), \(k = 2\), and \(p = -2\) (negative because it opens downward). Substitute these values to get the equation.
Write the final equation of the parabola as \[x^2 = 4(-2)(y - 2)\] or simplified to \[x^2 = -8(y - 2)\].
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
3mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Parabola Definition and Properties
A parabola is the set of all points equidistant from a fixed point called the focus and a fixed line called the directrix. The vertex is the midpoint between the focus and directrix. The parabola opens away from the directrix, and its shape depends on the distance between the vertex and the focus.
Recommended video:
Properties of Parabolas
Equation of a Parabola with Vertical Axis
For a parabola with a vertical axis of symmetry, the standard form is (x - h)^2 = 4p(y - k), where (h, k) is the vertex and p is the distance from the vertex to the focus. If p is positive, the parabola opens upward; if negative, it opens downward.
Recommended video:
Horizontal Parabolas
Using the Directrix to Find the Parabola Equation
The directrix is a line equidistant from the vertex as the focus but in the opposite direction. Knowing the directrix's equation helps determine p and the vertex's position, which are essential to write the parabola's equation accurately.
Recommended video:
Solving Exponential Equations Using Logs
Watch next
Master Geometries from Conic Sections with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Multiple Choice
11
views
