Solve the given linear equation, then check your answer − ( h + 3 ) = 11 -\left(h+3\right)=11

we're asked to solve the given linear equation, then check our answer. The equation we're given here is negative h plus three equals 11. The first thing I wanna do here is go ahead and distribute this negative into my parentheses here. This will give me a negative h minus three equals 11. Now from here, I can begin using my properties of equality to solve. I, my goal here is to get that h by itself. And my first step in doing that is going ahead and getting rid of this negative three by adding three to both sides. So that three will cancel and I'll end up with a negative H equals 11 plus three, which is 14. Now I have a negative on this H here. In order to get rid of that, I I can go ahead and divide by a negative one. And if I do that here, that will cancel out, leaving me with just h. And 14 divided by negative one will give me negative 14, and this is my solution. Now there are actually a couple of different ways I could have chosen to solve this. Instead of distributing that negative at the beginning, I could have actually started off here by dividing that negative over so that I then just had h plus three equals negative 11. In doing this, I would have gotten the same exact answer. Now another thing that I could have done differently is once I got to this step, if I did end up distributing that negative, I could have added my h over to the other side instead of using my division property of equality in order to cancel my negative. There are often multiple ways to get to the correct answer, and your steps won't always be the exact same as the steps that I take. But you still should get the same exact answer no matter what way you're choosing to solve. Just pay careful attention to each of your steps and always ask for help if you need it. Now one additional thing we want to do here is check our answer. So we can do that by taking our negative 14 and plugging it back into our original equation. Doing that would give me negative negative 14 plus three. And we wanna know, is this a true statement? Is this going to be equal to 11? Now negative 14 plus three is gonna be negative 11. So this is negative, negative 11. We want to know is this equal to 11? We know that two negatives make a positive, so this becomes 11 and I get that 11 equals 11. This is definitely a true statement, so I know that I got my correct answer. So even if you went about solving this equation slightly differently by, for example, taking that negative and dividing it over to the other side from the beginning, you still should end up with a true statement when you go back to check your answer. This will always tell you whether or not you solved your problem correctly. I'll see you in the next one.

Solve the given linear equation, then check your answer−(h+3)=11-\left(h+3\right)=11

h=−113h=-\frac{11}{3}h=−311

Table of contents

Skip topic navigation

1. Review of Real Numbers2h 43m

Simplifying Fractions
30m

Evaluating Exponents
29m

Evaluating Expressions
15m

Translating Phrases to Expressions
16m

Translating Sentences to Equations
9m

The Distributive Property
17m

Simplifying Expressions
44m

2. Linear Equations and Inequalities5h 35m

Solving Linear Equations
2h 23m

Linear Inequalities in One Variable
46m

Set Operations and Compound Inequalities
1h 7m

Absolute Value Equations
38m

Absolute Value Inequalities
39m

3. Solving Word Problems2h 46m

Introduction to Problem Solving
37m

Formulas
25m

Percent Problem Solving
59m

Mixture Problem Solving
43m

4. Graphs and Functions5h 12m

The Rectangular Coordinate System
44m

Graph Linear Equations in Two Variables
24m

Graph Linear Equations Using Intercepts
23m

Slope of a Line
44m

Slope-Intercept Form
38m

Point Slope Form
22m

Linear Inequalities in Two Variables
28m

Introduction to Relations and Functions
53m

Function Notation
15m

Composition of Functions
17m

5. Systems of Linear Equations1h 53m

Solving Systems of Linear Equations by Graphing
29m

Solving Systems of Linear Equations by Substitution
15m

Solving Systems of Linear Equations by Elimination
45m

Systems of Linear Inequalities
23m

6. Exponents, Polynomials, and Polynomial Functions3h 17m

The Product Rule
9m

The Quotient Rule
10m

Intro to the Power Rules
17m

The Power of a Quotient Rule
13m

Negative Exponents
24m

Simplifying Exponential Expressions Using All Exponent Rules
6m

Intro to Polynomials
21m

Adding and Subtracting Polynomials
20m

Multiplying Polynomials
38m

Special Products
34m

7. Factoring2h 49m

Factoring by Greatest Common Factor & Grouping
37m

Factoring Trinomials of the Form x² + bx + c
11m

Factoring Trinomials of the Form ax² + bx + c
37m

Factoring Special Products
41m

Quadratic Equations & Applications
41m

8. Rational Expressions and Functions3h 44m

Simplifying Rational Expressions
42m

Multiplying and Dividing Rational Expressions
25m

Adding and Subtracting Rational Expressions with Common Denominators
19m

Least Common Denominators
32m

Adding and Subtracting Rational Expressions with Different Denominators
32m

Rational Equations
44m

Direct & Inverse Variation
27m

9. Roots, Radicals, and Complex Numbers3h 57m

Introduction to Radical Expressions
47m

Simplifying Radical Expressions
47m

Adding and Subtracting Radicals
19m

Multiplying, Dividing, and Rationalizing Radicals
53m

Introduction to Complex Numbers
18m

Multiplying and Dividing Complex Numbers
51m

10. Quadratic Equations and Functions3h 1m

The Square Root Property
25m

Completing the Square
26m

The Quadratic Formula
40m

Graphing Quadratic Equations
1h 28m

11. Inverse, Exponential, & Logarithmic Functions2h 30m

Introduction to Inverse Functions
25m

Exponential Functions
35m

Introduction to Logarithmic Functions
33m

Properties of Logarithms
54m

12. Conic Sections & Systems of Nonlinear Equations2h 24m

Graphing Circles
32m

Ellipses
35m

Parabolas
35m

Hyperbolas
41m

13. Sequences, Series, and the Binomial Theorem1h 50m

Introduction to Sequences
40m

Arithmetic Sequences
27m

Geometric Sequences
29m

Factorials
13m

2. Linear Equations and Inequalities

Solving Linear Equations

Intermediate Algebra

2. Linear Equations and Inequalities

Solving Linear Equations

Previous problemNext problem

Struggling with Intermediate Algebra?

Join thousands of students who trust us to help them ace their exams!

Multiple Choice

Solve the given linear equation, then check your answer
$- (h + 3) = 11$

$h=-14$

$h=-$\frac{11}{3}$$

$h=-33$

$h=33$

0 Comments

Previous problemNext problem

Verified step by step guidance

Start with the given equation: $-\left(h + 3\right) = 11$.

Remove the negative sign by multiplying both sides of the equation by $-1$ to isolate the expression inside the parentheses: $h + 3 = -11$.

Next, solve for $h$ by subtracting $3$ from both sides: $h = -11 - 3$.

Simplify the right side to find the value of $h$ (do not calculate the final number here, just write the expression).

Finally, check your solution by substituting the value of $h$ back into the original equation to verify that both sides are equal.

5:27m

Watch next

Master Solving Linear Equations with Fraction or Decimal Coefficients Example 7 with a bite sized video explanation from Patrick Ford

Struggling with Intermediate Algebra?

Solve the given linear equation, then check your answer−(h+3)=11-\(\left\)(h+3\(\right\))=11

Watch next

Solve the given linear equation, then check your answer
$- (h + 3) = 11$