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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 5, Problem 5.4.45a

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.
(a) If ƒ is symmetric about the line 𝓍 = 2 , then ∫₀⁴ ƒ(𝓍) d𝓍 = 2 ∫₀² ƒ(𝓍) d𝓍.

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Step 1: Begin by understanding the symmetry of the function ƒ about the line 𝓍 = 2. A function is symmetric about a vertical line if, for every point (𝓍, ƒ(𝓍)) on the graph, there exists a corresponding point (4 - 𝓍, ƒ(𝓍)) that mirrors it across the line 𝓍 = 2.
Step 2: Use the property of symmetry to analyze the integral. If ƒ is symmetric about 𝓍 = 2, then the area under the curve from 𝓍 = 0 to 𝓍 = 2 is equal to the area under the curve from 𝓍 = 2 to 𝓍 = 4. This implies that the total integral from 𝓍 = 0 to 𝓍 = 4 can be expressed as twice the integral from 𝓍 = 0 to 𝓍 = 2.
Step 3: Write the integral expression mathematically. Using symmetry, we can state: ∫₀⁴ ƒ(𝓍) d𝓍 = ∫₀² ƒ(𝓍) d𝓍 + ∫₂⁴ ƒ(𝓍) d𝓍. Since the function is symmetric about 𝓍 = 2, ∫₂⁴ ƒ(𝓍) d𝓍 = ∫₀² ƒ(𝓍) d𝓍.
Step 4: Substitute the equality derived from symmetry into the original integral expression. This gives: ∫₀⁴ ƒ(𝓍) d𝓍 = ∫₀² ƒ(𝓍) d𝓍 + ∫₀² ƒ(𝓍) d𝓍 = 2 ∫₀² ƒ(𝓍) d𝓍.
Step 5: Conclude that the statement is true based on the symmetry of the function about the line 𝓍 = 2. The integral from 𝓍 = 0 to 𝓍 = 4 is indeed twice the integral from 𝓍 = 0 to 𝓍 = 2.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Symmetry in Functions

A function is symmetric about a vertical line, such as x = 2, if for every point (a, f(a)) on the graph, there is a corresponding point (4-a, f(a)). This means that the function's values are mirrored across the line x = 2, which can affect the evaluation of integrals over symmetric intervals.
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Properties of Functions

Definite Integrals

A definite integral, represented as ∫ₐᵇ f(x) dx, calculates the area under the curve of the function f(x) from x = a to x = b. The properties of definite integrals, including linearity and the ability to split intervals, are crucial for evaluating integrals over symmetric intervals and understanding how symmetry impacts the integral's value.
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Definition of the Definite Integral

Properties of Integrals and Symmetry

When a function is symmetric about a vertical line, the area under the curve from one side of the line can be related to the area from the other side. Specifically, if f is symmetric about x = 2, then the integral from 0 to 4 can be expressed as the sum of two equal integrals from 0 to 2, leading to the relationship ∫₀⁴ f(x) dx = 2 ∫₀² f(x) dx.
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Related Practice
Textbook Question

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume ƒ, ƒ', and ƒ'' are continuous functions for all real numbers.                                                                                                                                                           

                                                                                                                                                                    

(a) ∫ ƒ(𝓍) ƒ'(𝓍) d𝓍 = ½ (ƒ(𝓍))² + C.

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Textbook Question

Symmetry properties Suppose ∫₀⁴ ƒ(𝓍) d𝓍 = 10 and ∫₀⁴ g(𝓍) d𝓍 = 20. Furthermore, suppose ƒ is an even function and g is an odd function. Evaluate the following integrals.


(e) ∫₋₂² 3𝓍ƒ(𝓍)d𝓍

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Textbook Question

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

(a) Consider the linear function ƒ(𝓍) = 2x + 5 and the region bounded by its graph and the x-axis on the interval [3,6]. Suppose the area of this region is approximated using midpoint Riemann sums. Then the approximations give the exact area of the region for any number of subintervals.

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Textbook Question

Symmetry properties Suppose ∫₀⁴ ƒ(𝓍) d𝓍 = 10 and ∫₀⁴ g(𝓍) d𝓍 = 20. Furthermore, suppose ƒ is an even function and g is an odd function. Evaluate the following integrals.


(a) ∫₋₄⁴ ƒ(𝓍) d𝓍

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Textbook Question

Approximating displacement The velocity in ft/s of an object moving along a line is given by v = 3t² + 1 on the interval 0 ≤ t ≤ 4, where t is measured in seconds.

(a) Divide the interval [0,4] into n = 4 subintervals, [0,1] , [1.2] , [2,3] , and [3,4]. On each subinterval, assume the object moves at a constant velocity equal to v evaluated at the midpoint of the subinterval, and use these approximations to estimate the displacement of the object on [0, 4] (see part (a) of the figure)

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Textbook Question

Symmetry properties Suppose ∫₀⁴ ƒ(𝓍) d𝓍 = 10 and ∫₀⁴ g(𝓍) d𝓍 = 20. Furthermore, suppose ƒ is an even function and g is an odd function. Evaluate the following integrals.


(c) ∫₋₄⁴ (4ƒ(𝓍) ― 3g(𝓍))d𝓍

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