Skip to main content
Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 11, Problem 11.1.9

Use of Tech Linear and quadratic approximation


a. Find the linear approximating polynomial for the following functions centered at the given point a.


b. Find the quadratic approximating polynomial for the following functions centered at a.


c Use the polynomials obtained in parts (a) and (b) to approximate the given quantity.


f(x) = 8x^(3/2), a=1; approximate 8 ⋅ 1.1^(3/2)

Verified step by step guidance
1
Step 1: Identify the function and the point of approximation. Here, the function is \(f(x) = 8x^{\frac{3}{2}}\) and the center point is \(a = 1\).
Step 2: Compute the value of the function at \(a\): calculate \(f(1) = 8 \times 1^{\frac{3}{2}}\).
Step 3: Find the first derivative of the function, \(f'(x)\). Use the power rule: \(f'(x) = 8 \times \frac{3}{2} x^{\frac{3}{2} - 1} = 12 x^{\frac{1}{2}}\).
Step 4: Evaluate the first derivative at \(a\): calculate \(f'(1) = 12 \times 1^{\frac{1}{2}}\).
Step 5: Write the linear approximating polynomial (the linearization) centered at \(a\): \(L(x) = f(a) + f'(a)(x - a)\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
7m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Linear Approximation (Linearization)

Linear approximation uses the tangent line at a point to estimate the value of a function near that point. It is given by L(x) = f(a) + f'(a)(x - a), where f'(a) is the derivative at a. This method simplifies complex functions to linear ones for easier calculation of nearby values.
Recommended video:
07:17
Linearization

Quadratic Approximation (Second-Order Taylor Polynomial)

Quadratic approximation extends linear approximation by including the second derivative, providing a better estimate near the point a. It is expressed as Q(x) = f(a) + f'(a)(x - a) + (f''(a)/2)(x - a)^2, capturing curvature and improving accuracy over linearization.
Recommended video:
07:00
Taylor Polynomials

Derivative and Higher-Order Derivatives

Derivatives measure the rate of change of a function and are essential for constructing approximations. The first derivative gives the slope for linear approximation, while the second derivative indicates concavity, crucial for quadratic approximation. Calculating these derivatives at the point a is key to forming the approximating polynomials.
Recommended video:
02:42
Higher Order Derivatives