Clever substitution Evaluate ∫ dx/(1 + sin x + cos x) using the substitution x=2 tan⁻¹ θ. The identities sin x = 2 sin(x/2) cos(x/2) and cos x =cos²(x/2) − sin²(x/2) are helpful.
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
11. Integrals of Inverse, Exponential, & Logarithmic Functions
Integrals Involving Logarithmic Functions
Problem 7.3.63
Textbook Question
63–68. Definite integrals Evaluate the following definite integrals. Use Theorem 7.7 to express your answer in terms of logarithms.
∫₁ᵉ^² dx/x√(ln²x + 1)
Verified step by step guidance1
Identify the integral to be evaluated: \(\displaystyle \int_1^{e^2} \frac{1}{x \sqrt{(\ln x)^2 + 1}} \, dx\).
Recognize that the integrand involves \(\ln x\) and its derivative. Consider the substitution \(t = \ln x\), which implies \(dt = \frac{1}{x} dx\).
Rewrite the integral in terms of \(t\): since \(x\) goes from 1 to \(e^2\), then \(t\) goes from \(\ln 1 = 0\) to \(\ln e^2 = 2\). The integral becomes \(\int_0^2 \frac{1}{\sqrt{t^2 + 1}} \, dt\).
Recall that \(\int \frac{1}{\sqrt{t^2 + 1}} \, dt\) is a standard integral whose antiderivative is \(\sinh^{-1}(t)\) or equivalently \(\ln(t + \sqrt{t^2 + 1})\) (this is Theorem 7.7, expressing inverse hyperbolic sine in terms of logarithms).
Evaluate the definite integral by substituting the limits \(t=0\) and \(t=2\) into the antiderivative \(\ln(t + \sqrt{t^2 + 1})\) and subtracting: \(\left. \ln(t + \sqrt{t^2 + 1}) \right|_0^2\).
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
3mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Definite Integrals
A definite integral calculates the net area under a curve between two specific limits. It is represented as ∫_a^b f(x) dx, where a and b are the lower and upper bounds. Evaluating definite integrals often involves finding an antiderivative and then applying the Fundamental Theorem of Calculus.
Recommended video:
Definition of the Definite Integral
Substitution Method
The substitution method simplifies integrals by changing variables to transform the integral into a more manageable form. Typically, a substitution u = g(x) is chosen so that du replaces part of the integrand, making integration straightforward. This method is especially useful when the integrand contains composite functions.
Recommended video:
Euler's Method
Logarithmic Functions and Their Properties
Logarithmic functions, such as ln(x), are inverses of exponential functions and have properties that simplify expressions involving products, quotients, and powers. In integration, expressing answers in terms of logarithms often involves recognizing derivatives of ln(x) and using log rules to rewrite results clearly.
Recommended video:
Properties of Functions
Watch next
Master Integrals Resulting in Natural Logs with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Textbook Question
7
views
