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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 10, Problem 10.1.31c

27–34. Working with sequences Several terms of a sequence {aₙ}ₙ₌₁∞ are given.
c. Find an explicit formula for the nth term of the sequence.


{1, 3, 9, 27, 81, ......}

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1
Identify the pattern in the given sequence: {1, 3, 9, 27, 81, ...}. Notice how each term relates to the previous one by multiplication.
Recognize that the sequence is geometric because each term is obtained by multiplying the previous term by a constant ratio. Calculate the common ratio \( r \) by dividing the second term by the first term: \( r = \frac{3}{1} \).
Recall the general formula for the nth term of a geometric sequence: \( a_n = a_1 \times r^{n-1} \), where \( a_1 \) is the first term and \( r \) is the common ratio.
Substitute the known values into the formula: \( a_1 = 1 \) and \( r = 3 \), so the explicit formula becomes \( a_n = 1 \times 3^{n-1} \).
Simplify the formula if possible. In this case, the explicit formula for the nth term is \( a_n = 3^{n-1} \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Sequences and Terms

A sequence is an ordered list of numbers where each number is called a term. The nth term, denoted as aₙ, represents the value at position n in the sequence. Understanding how terms progress helps in identifying patterns and formulating explicit expressions.
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Introduction to Sequences

Geometric Sequences

A geometric sequence is one where each term is found by multiplying the previous term by a constant ratio. For example, in the sequence {1, 3, 9, 27, 81, ...}, each term is multiplied by 3. Recognizing this pattern is key to finding the explicit formula.
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Geometric Sequences - Recursive Formula

Explicit Formula for nth Term

The explicit formula expresses the nth term directly in terms of n, without needing previous terms. For geometric sequences, it is generally aₙ = a₁ * r^(n-1), where a₁ is the first term and r is the common ratio. This formula allows quick calculation of any term.
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Related Practice
Textbook Question

Explain why or why not

Determine whether the following statements are true and give an explanation or counterexample.


c.The convergent sequences {aₙ} and {bₙ} differ in their first 100 terms, but aₙ = bₙ for n > 100.

It follows that limₙ→∞aₙ = limₙ→∞bₙ.

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Textbook Question

{Use of Tech} Periodic dosing

Many people take aspirin on a regular basis as a preventive measure for heart disease. Suppose a person takes 80 mg of aspirin every 24 hours. Assume aspirin has a half-life of 24 hours; that is, every 24 hours, half of the drug in the blood is eliminated.


c.Assuming the sequence has a limit, confirm the result of part (b) by finding the limit of {dₙ} directly.

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Textbook Question

39–40. {Use of Tech} Lower and upper bounds of a series

For each convergent series and given value of n, use Theorem 10.13 to complete the following.


c. Find lower and upper bounds (Lₙ and Uₙ, respectively) for the exact value of the series.


39. ∑ (k = 1 to ∞) 1 / k⁷ ; n = 2

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Textbook Question

Explain why or why not

Determine whether the following statements are true and give an explanation or counterexample.


c.If the terms of the sequence {aₙ} are positive and increasing, then the sequence of partial sums for the series∑⁽∞⁾ₖ₌₁aₖ diverges.

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Textbook Question

27–34. Working with sequences Several terms of a sequence {aₙ}ₙ₌₁∞ are given.

c. Find an explicit formula for the nth term of the sequence.


{-5, 5, -5, 5, ......}

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Textbook Question

41–44. {Use of Tech} Remainders and estimates Consider the following convergent series.


c. Find lower and upper bounds (Lₙ and Uₙ, respectively) on the exact value of the series.


41. ∑ (k = 1 to ∞) 1 / k⁶

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