A useful substitution Replace x with x−1 in the series ln (1+x) = ∑ₖ₌₁∞ ((−1)ᵏ⁺¹ xᵏ)/k to obtain a power series for ln x centered at x = 1. What is the interval of convergence for the new power series?
Table of contents
- 0. Functions7h 54m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
15. Power Series
Introduction to Power Series
Problem 11.2.67
Textbook Question
Series to functions Find the function represented by the following series, and find the interval of convergence of the series. (Not all these series are power series.)
∑ₖ₌₀∞(√x − 2)ᵏ
Verified step by step guidance1
Recognize that the given series is a geometric series of the form \(\sum_{k=0}^\infty r^k\), where the common ratio \(r\) is \(\sqrt{x} - 2\).
Recall that a geometric series \(\sum_{k=0}^\infty r^k\) converges to the function \(\frac{1}{1-r}\) when \(|r| < 1\).
Write the function represented by the series as \(f(x) = \frac{1}{1 - (\sqrt{x} - 2)}\).
Simplify the denominator to get \(f(x) = \frac{1}{1 - \sqrt{x} + 2} = \frac{1}{3 - \sqrt{x}}\).
Determine the interval of convergence by solving the inequality \(|\sqrt{x} - 2| < 1\). This involves considering the values of \(x\) for which the absolute value condition holds, and also ensuring \(x \geq 0\) since \(\sqrt{x}\) is defined for non-negative \(x\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Geometric Series
A geometric series is a sum of terms where each term is a constant multiple (common ratio) of the previous one. It converges to a finite value if the absolute value of the ratio is less than 1, and its sum is given by S = a / (1 - r), where a is the first term and r is the ratio.
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Interval of Convergence
The interval of convergence is the set of all x-values for which a given series converges. For power or related series, it is found by applying convergence tests, often involving inequalities on the variable to ensure the series terms approach zero.
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Manipulating Series with Functions
To find the function represented by a series, one must recognize the pattern of terms and rewrite the series in a closed form. This often involves identifying the series type and substituting expressions (like √x − 2) as the variable to simplify and find the sum function.
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