Shifting power series If the power series f(x)=∑ cₖ xᵏ has an interval of convergence of |x|<R, what is the interval of convergence of the power series for f(x−a), where a ≠ 0 is a real number?
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- 1. Limits and Continuity2h 2m
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15. Power Series
Introduction to Power Series
Problem 11.2.74
Textbook Question
Exponential function In Section 11.3, we show that the power series for the exponential function centered at 0 is
eˣ = ∑ₖ₌₀∞ (xᵏ)/k!, for −∞ < x < ∞
Use the methods of this section to find the power series centered at 0 for the following functions. Give the interval of convergence for the resulting series.
f(x) = x²eˣ
Verified step by step guidance1
Recall the power series expansion for the exponential function centered at 0:
\[e^{x} = \sum_{k=0}^{\infty} \frac{x^{k}}{k!}\]
To find the power series for \[f(x) = x^{2} e^{x}\], multiply the entire series for \[e^{x}\] by \[x^{2}\]:
\[f(x) = x^{2} \sum_{k=0}^{\infty} \frac{x^{k}}{k!} = \sum_{k=0}^{\infty} \frac{x^{k+2}}{k!}\]
Rewrite the series to express it in a standard power series form \[\sum_{n=0}^{\infty} a_{n} x^{n}\] by changing the index of summation. Let \[n = k + 2\], so when \[k=0\], \[n=2\]. Thus,
\[f(x) = \sum_{n=2}^{\infty} \frac{x^{n}}{(n-2)!}\]
Identify the coefficients \[a_{n}\] of the power series:
For \[n \geq 2\], \[a_{n} = \frac{1}{(n-2)!}\], and for \[n < 2\], \[a_{n} = 0\] since the series starts at \[n=2\].
Determine the interval of convergence. Since the original series for \[e^{x}\] converges for all real \[x\] (i.e., \[(-\infty, \infty)\]), multiplying by \[x^{2}\] does not change the radius or interval of convergence. Therefore, the interval of convergence for \[f(x)\] is also \[(-\infty, \infty)\].
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Power Series Representation
A power series expresses a function as an infinite sum of terms involving powers of x, typically centered at a point (here, 0). Understanding how to write functions as power series allows approximation and analysis of functions using polynomials. For example, eˣ can be represented as ∑ₖ₌₀∞ (xᵏ)/k!.
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Intro to Power Series
Manipulation of Power Series
To find the power series of f(x) = x²eˣ, multiply the known series for eˣ by x² term-by-term. This involves shifting powers and coefficients accordingly. Mastery of series operations like multiplication by xⁿ and term-wise addition or differentiation is essential.
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Intro to Power Series
Interval of Convergence
The interval of convergence is the set of x-values for which the power series converges to the function. For eˣ, the series converges for all real x (−∞, ∞). Multiplying by x² does not change this interval, so the resulting series also converges everywhere.
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Interval of Convergence
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