Skip to main content
Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 5, Problem 5.2.29

Area versus net area Graph the following functions. Then use geometry (not Riemann sums) to find the area and the net area of the region described.
The region between the graph of y = 1 - |x| and the x-axis, for -2 ≤ x ≤ 2

Verified step by step guidance
1
First, understand the function given: \(y = 1 - |x|\). This is a V-shaped graph with its vertex at \((0,1)\) and it intersects the x-axis where \$1 - |x| = 0$.
Find the points where the graph intersects the x-axis by solving \$1 - |x| = 0\(. This gives \)|x| = 1\(, so the points are \)x = -1\( and \)x = 1$.
Sketch the graph between \(x = -2\) and \(x = 2\). Note that for \(|x| > 1\), the function \(y = 1 - |x|\) is negative, so the graph lies below the x-axis on the intervals \([-2, -1]\) and \([1, 2]\), and above the x-axis on \([-1, 1]\).
To find the net area, calculate the definite integral of \(y = 1 - |x|\) from \(-2\) to \(2\). Since the function changes sign, the net area is the sum of the positive area above the x-axis minus the area below the x-axis.
To find the total (or geometric) area, calculate the area of the two triangles formed above the x-axis on \([-1, 1]\) and the two triangles below the x-axis on \([-2, -1]\) and \([1, 2]\), then add their absolute values together.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
4m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Net Area

Net area refers to the integral of a function over an interval, accounting for areas above the x-axis as positive and below as negative. It represents the algebraic sum of areas, which can result in cancellation when parts lie below the x-axis.
Recommended video:
05:06
Finding Area When Bounds Are Not Given

Area Between a Curve and the x-axis

The area between a curve and the x-axis is the total size of the region bounded by the graph and the axis, always taken as positive. When the function dips below the x-axis, the area is found by integrating the absolute value or by geometric methods considering separate regions.
Recommended video:
05:23
Finding Area Between Curves on a Given Interval

Using Geometry to Find Areas

Instead of integration, geometric shapes like triangles and trapezoids can be used to find areas under curves when the graph forms simple shapes. This approach involves identifying shapes formed by the function and the x-axis and calculating their areas using known formulas.
Recommended video:
05:06
Finding Area When Bounds Are Not Given
Related Practice
Textbook Question

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 ∫ [(√𝓍 + 1)⁴ / 2√𝓍 d𝓍

65
views
Textbook Question

Average values Find the average value of the following functions on the given interval. Draw a graph of the function and indicate the average value.

ƒ(𝓍) = 𝓍ⁿ on [0,1] , for any positive integer n

87
views
Textbook Question

Average values Find the average value of the following functions on the given interval. Draw a graph of the function and indicate the average value.

ƒ(𝓍) = 𝓍³ on [―1, 1]

125
views
Textbook Question

Definite integrals from graphs The figure shows the areas of regions bounded by the graph of ƒ and the 𝓍-axis. Evaluate the following integrals.


∫ₐ⁰ ƒ(𝓍) d𝓍

71
views
Textbook Question

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 ∫ 𝓍eˣ² d𝓍

71
views
Textbook Question

Indefinite integrals Use a change of variables or Table 5.6 to evaluate the following indefinite integrals. Check your work by differentiating.                                                                                  

                                                                                                                                                                    

 ∫ 𝓍³ (𝓍⁴ + 16)⁶ d𝓍

56
views