Surface area of a cone Find the surface area of a cone (excluding the base) with radius 4 and height 8 using integration and a surface area integral.
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- 0. Functions7h 54m
- Introduction to Functions16m
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- Properties of Functions9m
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- Transformations5m
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- 1. Limits and Continuity2h 2m
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- 7. Antiderivatives & Indefinite Integrals1h 26m
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- 10. Physics Applications of Integrals 3h 16m
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- 12. Techniques of Integration7h 41m
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9. Graphical Applications of Integrals
Introduction to Volume & Disk Method
Problem 6.3.20
Textbook Question
Let R be the region bounded by the following curves. Find the volume of the solid generated when R is revolved about the given axis.
y=1 / 4√1 − x^2,y=0,x=0, and x=12; about the x-axis

Verified step by step guidance1
Identify the region R bounded by the curves: \(y = \frac{1}{4} \sqrt{1 - x^2}\), \(y = 0\), \(x = 0\), and \(x = \frac{1}{2}\).
Since the region is revolved about the x-axis, use the disk method to find the volume. The volume of the solid is given by the integral \(V = \pi \int_a^b [f(x)]^2 \, dx\), where \(f(x)\) is the radius of the disk at position \(x\).
Here, the radius of each disk is the function \(y = \frac{1}{4} \sqrt{1 - x^2}\), so the volume integral becomes \(V = \pi \int_0^{\frac{1}{2}} \left( \frac{1}{4} \sqrt{1 - x^2} \right)^2 \, dx\).
Simplify the integrand inside the integral: \(\left( \frac{1}{4} \sqrt{1 - x^2} \right)^2 = \frac{1}{16} (1 - x^2)\), so the integral is \(V = \pi \int_0^{\frac{1}{2}} \frac{1}{16} (1 - x^2) \, dx\).
Evaluate the integral \(\int_0^{\frac{1}{2}} (1 - x^2) \, dx\) and multiply the result by \(\frac{\pi}{16}\) to find the volume of the solid.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Volume of Solids of Revolution
This concept involves finding the volume of a 3D solid formed by rotating a 2D region around an axis. The volume can be computed using methods like the disk/washer or shell method, depending on the axis of rotation and the shape of the region.
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Disk Method
The disk method calculates volume by slicing the solid perpendicular to the axis of rotation into thin disks. Each disk's volume is approximated by π(radius)^2 × thickness, where the radius is the distance from the axis to the curve. Integrating these volumes over the interval gives the total volume.
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Disk Method Using y-Axis
Definite Integration with Function Boundaries
Definite integration is used to sum infinitely many infinitesimal volumes. The limits of integration correspond to the bounds of the region (here, x=0 to x=1/2). The integrand is derived from the function describing the curve, which in this case is y = (1/4)√(1−x²).
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